The figure below shows a circuit containing an electromotive force, a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (2). The voltage drop across the capacitor is 2, where Q is the charge (in coulombs), so in this case Kirchhoff's law gives E(t). RI + But I = dQ (see this example), so we have dt dQ 응= E(t). dt Suppose the resistance is 5 2, the capacitance is 0.05 F, a battery gives a constant voltage of 40 V, and the initial charge is Q = 0 C. E) R Find the charge Q (in C) at time t. Q(t) = Find the current I (in A) at time t. I(t) = A

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The figure below shows a circuit containing an electromotive force, a capacitor with a capacitance of C farads (F), and a resistor with a
resistance of R ohms (N). The voltage drop across the capacitor is
where Q is the charge (in coulombs), so in this case Kirchhoff's law
gives
= E(t).
RI +
do
(see this example), so we have
dt
But I =
+
2 = E(t).
dt
Suppose the resistance is 5 N, the capacitance is 0.05 F, a battery gives a constant voltage of 40 V, and the initial charge is Q = 0 C.
E
Find the charge Q (in C) at time t.
Q(t) =
Find the current I (in A) at time t.
I(t) =
A
Transcribed Image Text:The figure below shows a circuit containing an electromotive force, a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (N). The voltage drop across the capacitor is where Q is the charge (in coulombs), so in this case Kirchhoff's law gives = E(t). RI + do (see this example), so we have dt But I = + 2 = E(t). dt Suppose the resistance is 5 N, the capacitance is 0.05 F, a battery gives a constant voltage of 40 V, and the initial charge is Q = 0 C. E Find the charge Q (in C) at time t. Q(t) = Find the current I (in A) at time t. I(t) = A
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