The figure below is a square. Find the length of side x in simplest radical form with a rational denominator. 12

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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The figure below is a square. Find the length of side xx in simplest radical form with a rational denominator.

**Problem Statement:**
The figure below is a square. Find the length of side \( x \) in simplest radical form with a rational denominator.

[Image Description]:
The image shows a square with one of its diagonal lines present. The square is tilted slightly to the left. One diagonal is marked with a label "12", indicating its length. One segment of a side of the square within the diagonal is labeled with an "x".

**Solution:**

To find the side length \( x \) of the square, which is the side of the square, we'll apply the properties of squares and the Pythagorean theorem.

Since the given shape is a square, all its sides are of equal length. The diagonals of a square are also equal and they intersect at right angles, forming two 45-45-90 right triangles.

The properties of a 45-45-90 triangle dictate that if the legs have length \( x \), the hypotenuse will be \( x\sqrt{2} \). Here, the hypotenuse is given as 12.

Given the the properties of 45-45-90 triangles:
\[ x\sqrt{2} = 12 \]

Solve for \( x \):
\[ x = \frac{12}{\sqrt{2}} \]

Rationalize the denominator:
\[ x = \frac{12}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} = \frac{12\sqrt{2}}{2} = 6\sqrt{2} \]

Therefore, the length of side \( x \) in simplest radical form with a rational denominator is \( 6\sqrt{2} \).
Transcribed Image Text:**Problem Statement:** The figure below is a square. Find the length of side \( x \) in simplest radical form with a rational denominator. [Image Description]: The image shows a square with one of its diagonal lines present. The square is tilted slightly to the left. One diagonal is marked with a label "12", indicating its length. One segment of a side of the square within the diagonal is labeled with an "x". **Solution:** To find the side length \( x \) of the square, which is the side of the square, we'll apply the properties of squares and the Pythagorean theorem. Since the given shape is a square, all its sides are of equal length. The diagonals of a square are also equal and they intersect at right angles, forming two 45-45-90 right triangles. The properties of a 45-45-90 triangle dictate that if the legs have length \( x \), the hypotenuse will be \( x\sqrt{2} \). Here, the hypotenuse is given as 12. Given the the properties of 45-45-90 triangles: \[ x\sqrt{2} = 12 \] Solve for \( x \): \[ x = \frac{12}{\sqrt{2}} \] Rationalize the denominator: \[ x = \frac{12}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} = \frac{12\sqrt{2}}{2} = 6\sqrt{2} \] Therefore, the length of side \( x \) in simplest radical form with a rational denominator is \( 6\sqrt{2} \).
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