The figure below gives the position of a 0.030 kg block oscillating in SHM on the end of a spring. On the horizontal axis, t1 = 0.020 sec. (a) What is the maximum kinetic energy of the block? (Hint: Measuring a slope will probably not be very accurate. Can you think of another approach?)   (b) How many times per second is the maximum kinetic energy reached?

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The figure below gives the position of a 0.030 kg block oscillating in SHM on the end of a spring. On the horizontal axis, t1 = 0.020 sec.

(a) What is the maximum kinetic energy of the block? (Hint: Measuring a slope will probably not be very accurate. Can you think of another approach?)

 

(b) How many times per second is the maximum kinetic energy reached?

x (cm)
8+
4
(ms)
-4
-8
Transcribed Image Text:x (cm) 8+ 4 (ms) -4 -8
Expert Solution
Step 1

Here the amplitude is A= 7cm

frequency f=12×0.02=25

ω=2πf

As the motion is SHM, the maximum kinetic energy will be

T=12mω2A2=12×0.03×2π×252×7×10-22=1.81Joule

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