The fifth ionization energy of O is 18.2 x 10-18 J. What is the maximum wavelength of radiation that will remove the fifth electron from 04+? nm
The fifth ionization energy of O is 18.2 x 10-18 J. What is the maximum wavelength of radiation that will remove the fifth electron from 04+? nm
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter6: Electronic Structure And The Periodic Table
Section: Chapter Questions
Problem 51QAP: How many unpaired electrons are there 111 the following ions? (a) V3+(b) Sn4+(c) I-(d) W4+
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![The fifth ionization energy of O is 18.2 x 10-18 J.
What is the maximum wavelength of radiation that will remove the fifth electron from O4+?
nm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F33281441-1e57-4fe7-bc2a-165fb9de3f22%2F807e350d-8f09-4b08-851f-5ddeb8f1f18d%2F6ep9q5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The fifth ionization energy of O is 18.2 x 10-18 J.
What is the maximum wavelength of radiation that will remove the fifth electron from O4+?
nm
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