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The face of a vertical dam has the shape of an isosceles triangle of altitude 4 m with an upper base of 6 m submerged vertically in the water. Find the force exerted by the water on the dam when the upper base is parallel to and 3 m below the surface of the water. (p = wight per unit volume water) 4 3y (A) F = p [₁ (142y) () dy 0 (B F = 5² (14 y - y²) dy 0 3 F = ·£³ (78- (7y - y²) dy 0 3 3y S² (7-3) ( ²2 ) C) (D F = P E) None of the choices dy

The face of a vertical dam has the shape of an isosceles triangle of altitude 4 m with an upper base of 6 m submerged vertically in the water. Find the force exerted by the water on the dam when the upper base is parallel to and 3 m below the surface of the water. (p = wight per unit volume water) 4 3y (A) F = p [₁ (142y) () dy 0 (B F = 5² (14 y - y²) dy 0 3 F = ·£³ (78- (7y - y²) dy 0 3 3y S² (7-3) ( ²2 ) C) (D F = P E) None of the choices dy

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The face of a vertical dam has the shape of an isosceles triangle of altitude 4 m with an upper base of 6 m submerged vertically in the water. Find the force exerted by the water on the dam when the upper base is parallel to and 3 m below the surface of the water.

The face of a vertical dam has the shape of an isosceles triangle of altitude 4 m with an upper base of 6 m submerged vertically in the water. Find the force exerted by the water on the dam when the upper base is parallel to and 3 m below the surface of the water. (p = wight per unit volume water) (A) F = P S² (14- 3y (142y) (-) dy ) ( ) 4 0 (B) S² F = (14 y - y²) dy 0 3 3 ⒸF-₂ F = (7y - y2) dy 0 3 3y D - [ 0 E None of the choices 3 F = P (7- y) ( ) dy
Transcribed Image Text:The face of a vertical dam has the shape of an isosceles triangle of altitude 4 m with an upper base of 6 m submerged vertically in the water. Find the force exerted by the water on the dam when the upper base is parallel to and 3 m below the surface of the water. (p = wight per unit volume water) (A) F = P S² (14- 3y (142y) (-) dy ) ( ) 4 0 (B) S² F = (14 y - y²) dy 0 3 3 ⒸF-₂ F = (7y - y2) dy 0 3 3y D - [ 0 E None of the choices 3 F = P (7- y) ( ) dy
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