The extent to which the tip condition affects the ther- mal performance of a fin depends on the fin geometry and thermal conductivity, as well as the convection coefficient. Consider an alloyed aluminum (k = 180 W/m · K) rectangular fin whose base temperature is T, = 100°C. The fin is exposed to a fluid of tempera- ture T. = 25°C, and a uniform convection coefficient of h = 100 W/m? ·K may be assumed for the fin surface. For a fin of length L = 10 mm, thickness t=1 mm, and width =1cm. determine the fin heat transfer rate per unit width qf, efficiency n, effec- tiveness 8, and tip temperature T(L)

The extent to which the tip condition affects the ther- mal performance of a fin depends on the fin geometry and thermal conductivity, as well as the convection coefficient. Consider an alloyed aluminum (k = 180 W/m · K) rectangular fin whose base temperature is T, = 100°C. The fin is exposed to a fluid of tempera- ture T. = 25°C, and a uniform convection coefficient of h = 100 W/m? ·K may be assumed for the fin surface. For a fin of length L = 10 mm, thickness t=1 mm, and width =1cm. determine the fin heat transfer rate per unit width qf, efficiency n, effec- tiveness 8, and tip temperature T(L)

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter7: Forced Convection Inside Tubes And Ducts

Section: Chapter Questions

Problem 7.53P

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plz answer this,ASAP,thx At high temperatures a nuclear reactor consists of a cylindrical wall composite as the fuel element thorium (k = 57 W/mK) wrapped in graphite (k = 3 W/mK) and helium gas flows through a circular cooling channel. Cylinder length 200 mm. Taking into account the helium temperature = 600°C and the convection coefficient, h= 200 W/m²K. When measured, the outside temperature is 100°C, and h = 5 W/m².K. Draw the electrical analogy, and calculate the overall heat transfer rate!
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uo 9:EV * ASIACELL l. Quize-1.pdf A diagram of a heat sink to be used in an electronic application is shown below. There are a total of 9 aluminium fins (k = 175 W/m K, C 900 J/kg K, p= 2700kg/ m') of rectangular cross-section, each 60 mm long, 40 mm wide and 1 mm thick. The spacing between adjacent fins, s, is 3 mm. The temperature of the base of the heat sink has a maximum design value of T, = 60°C, when the external air temperature T, is 20°C. Under these conditions, the extemal heat transfer coefficient h is 12 W/m K. The fin may be assumed to be sufficiently thin so that the heat transfer from the tip can be neglected. The surface temperature T, at a distance, x, from the base of the fin is given by: (T, -T, )cosh m(L-x) hP and A, is the cross sectional area. kA T-T, = where m? = sinh mL Determine the total convective heat transfer from the heat sink, the fin effectiveness and the fin efficiency. 40 mm 1 mm T, = 20°C h=12 W/mK 3 mm T, = 60°C N = 9 fins K = 175 W/m K 50 mm
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1. Determine the heat flow for (i) rectangular fins and (ii) triangular fin of 20 mm length and 3 mm base thickness. Thermal conductivity 100 W/m2K, base temperature = 120°C surrounding fluid temperature = 35°C. Determine also the fin effectiveness. 2. A circumferential fin on a pipe of 50 mm OD is 3 mm thick and 20 mm long. Using the property values and other parameters in 1, determine the: = 45 W/m K. Convection coefficient h= (i) heat flow and effectiveness (ii) If the pitch is 10 mm, determine the increase in heat flow for 1 m length of pipe. Also determine the total efficiency. Circumferential rectangular fin Rectangular and Triangular fins 100 100 80 80 2c 60 * 60 40 40 20 0.5 1.0 1.5 2.0 2.5 3.0 0.5 1.0 1.5 2.0 2.5 3.0 0.5 h 0.5 h kAP 1.5 1.5 L RAP Le = L+ A, = t(r2 - r) A, = 2M(r2,² – r,³) L =L+ "2, = r, + L Rectangular fin A, = tL, L = L A, = 2L, (Depth Triangular fin A, = L 20 Fin efficiency, %
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