The equilibrium equation for the formation of the complex PbBr42- is: Pb2+ + 4 Br = PbBr42. Since PbBr42- is a typical complex, which of the following would you expect to be true? 1. The Kf value is small (- power of 10) 2. At equilibrium, there will be more PbBr42- than free Pb2+ and Br- 3. The Kf value is large (+ power of 10) 4. At equilibrium, there will be more free Pb²+ and Br than PbBr42- 3 and 4 only 2 and 3 only O 1 and 4 only O 2 only O 1 and 2 only

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The equilibrium equation for the
formation of the complex PbBr42 is:
Pb2+ + 4 Br = PbBr42.
Since PbBr42- is a typical complex,
which of the following would you
expect to be true?
1. The Kf value is small (-
power of 10)
2. At equilibrium, there will be
more PbBr42- than free Pb2+ and Br-
3. The Kf value is large (+
power of 10)
4. At equilibrium, there will be
more free Pb²+ and Br than PbBr,2-
3 and 4 only
2 and 3 only
O 1 and 4 only
O 2 only
O 1 and 2 only
Transcribed Image Text:The equilibrium equation for the formation of the complex PbBr42 is: Pb2+ + 4 Br = PbBr42. Since PbBr42- is a typical complex, which of the following would you expect to be true? 1. The Kf value is small (- power of 10) 2. At equilibrium, there will be more PbBr42- than free Pb2+ and Br- 3. The Kf value is large (+ power of 10) 4. At equilibrium, there will be more free Pb²+ and Br than PbBr,2- 3 and 4 only 2 and 3 only O 1 and 4 only O 2 only O 1 and 2 only
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