The equilibrium constant Kp for the reaction 3A(g) + B(s) <--> C(g) + D(g) is 4.9 x 10 5 at 142 °C. What is Kc for this reaction? Recall that Kp =KCRT)An 80 R= 8.31446 J - K-1. mol 1 R= 0.0820573 L atm · K . mol Scientific notation in a canvas quiz is expressed as in the following example: 0.0012 = 1.2*10^-3
The equilibrium constant Kp for the reaction 3A(g) + B(s) <--> C(g) + D(g) is 4.9 x 10 5 at 142 °C. What is Kc for this reaction? Recall that Kp =KCRT)An 80 R= 8.31446 J - K-1. mol 1 R= 0.0820573 L atm · K . mol Scientific notation in a canvas quiz is expressed as in the following example: 0.0012 = 1.2*10^-3
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Equilibrium Constant Calculation**
The equilibrium constant \( K_p \) for the reaction:
\[ 3A(g) + B(s) \rightleftharpoons C(g) + D(g) \]
is \( 4.9 \times 10^{-5} \) at 142°C. What is \( K_c \) for this reaction?
Recall that \( K_p = K_c(RT)^{\Delta n} \)
Constants:
- \( R = 8.31446 \, \text{J} \cdot \text{K}^{-1} \cdot \text{mol}^{-1} \)
- \( R = 0.0820573 \, \text{L} \cdot \text{atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1} \)
**Scientific Notation Instruction:**
Scientific notation in a canvas quiz is expressed as in the following example:
- \( 0.0012 = 1.2 \times 10^{-3} \)
Type your answer in the space below.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F40daf55f-9b36-4034-9111-c8b1fc526fc5%2F255ea3c5-c35b-421b-b699-55046f874c44%2Fvxmyin_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Equilibrium Constant Calculation**
The equilibrium constant \( K_p \) for the reaction:
\[ 3A(g) + B(s) \rightleftharpoons C(g) + D(g) \]
is \( 4.9 \times 10^{-5} \) at 142°C. What is \( K_c \) for this reaction?
Recall that \( K_p = K_c(RT)^{\Delta n} \)
Constants:
- \( R = 8.31446 \, \text{J} \cdot \text{K}^{-1} \cdot \text{mol}^{-1} \)
- \( R = 0.0820573 \, \text{L} \cdot \text{atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1} \)
**Scientific Notation Instruction:**
Scientific notation in a canvas quiz is expressed as in the following example:
- \( 0.0012 = 1.2 \times 10^{-3} \)
Type your answer in the space below.
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