The equilibrium constant, K. for the following reaction is 6.30 at 723 K. Calculate K, for this reaction at this temperature. 2NH3(g) N2(g)+ 3H2(g)
The equilibrium constant, K. for the following reaction is 6.30 at 723 K. Calculate K, for this reaction at this temperature. 2NH3(g) N2(g)+ 3H2(g)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![**Problem Statement:**
The equilibrium constant, \( K_c \), for the following reaction is 6.30 at 723 K. Calculate \( K_p \) for this reaction at this temperature.
**Reaction:**
\[ 2 \text{NH}_3(g) \rightleftharpoons \text{N}_2(g) + 3 \text{H}_2(g) \]
**Instructions:**
1. Use the given equilibrium constant, \( K_c \), to calculate the equilibrium constant for pressure, \( K_p \).
2. Remember to apply the relationship between \( K_c \) and \( K_p \):
\[
K_p = K_c(RT)^{\Delta n}
\]
where \( R \) is the universal gas constant, \( T \) is the temperature in Kelvin, and \( \Delta n \) is the change in moles of gas (moles of products - moles of reactants).
**Interaction Elements:**
- **Submit Answer**: Button to submit your calculation.
- **Retry Entire Group**: Option to retry the process if needed.
**Additional Notes:**
- Ensure all calculations adhere to correct scientific principles.
- Use references if necessary to access any required constants or conversion factors.
- You have 9 more group attempts remaining to solve this problem.
**Graph/Diagram Explanation:**
There are no graphs or diagrams included in the image.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6bfb8691-d1db-4ddc-9d6d-d840f1ac88cb%2Fdcf94c74-e3cb-4a57-8148-b1e9b5088f93%2Fmodo32c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
The equilibrium constant, \( K_c \), for the following reaction is 6.30 at 723 K. Calculate \( K_p \) for this reaction at this temperature.
**Reaction:**
\[ 2 \text{NH}_3(g) \rightleftharpoons \text{N}_2(g) + 3 \text{H}_2(g) \]
**Instructions:**
1. Use the given equilibrium constant, \( K_c \), to calculate the equilibrium constant for pressure, \( K_p \).
2. Remember to apply the relationship between \( K_c \) and \( K_p \):
\[
K_p = K_c(RT)^{\Delta n}
\]
where \( R \) is the universal gas constant, \( T \) is the temperature in Kelvin, and \( \Delta n \) is the change in moles of gas (moles of products - moles of reactants).
**Interaction Elements:**
- **Submit Answer**: Button to submit your calculation.
- **Retry Entire Group**: Option to retry the process if needed.
**Additional Notes:**
- Ensure all calculations adhere to correct scientific principles.
- Use references if necessary to access any required constants or conversion factors.
- You have 9 more group attempts remaining to solve this problem.
**Graph/Diagram Explanation:**
There are no graphs or diagrams included in the image.
![**Title: Calculating Equilibrium Constants for Chemical Reactions**
**Introduction:**
In chemical thermodynamics, understanding the equilibrium constant is essential for predicting the concentrations of reactants and products in a chemical reaction at equilibrium. This topic explores the relationship between the equilibrium constants \( K_p \) and \( K_c \) and guides you through a calculation using the reaction of ammonium chloride.
**Problem Statement:**
The equilibrium constant, \( K_p \), for the given reaction is \( 1.04 \times 10^{-2} \) at \( 548 \, \text{K} \). You are required to calculate \( K_c \) for this reaction at the same temperature.
**Reaction:**
\[
\text{NH}_4\text{Cl(s)} \rightleftharpoons \text{NH}_3\text{(g)} + \text{HCl(g)}
\]
**Calculation:**
For the conversion between \( K_p \) and \( K_c \), use the formula:
\[
K_p = K_c(RT)^{\Delta n}
\]
where:
- \( \Delta n \) is the change in moles of gas (products - reactants).
- \( R \) is the ideal gas constant (\(0.0821 \, \text{L atm/mol K}\)).
- \( T \) is the temperature in Kelvin.
**Input Field:**
- \( K_c \) (Enter your calculated value here.)
**Submission:**
- Use the "Submit Answer" button to check your result.
- Use the "Retry Entire Group" if you need to attempt the calculation again.
**Note:**
Remember that \( \Delta n \) for the reaction is calculated from the gas moles. Here, \( \Delta n = 2 - 0 = 2 \).
Good luck with your calculation! Feel free to use the "References" link for any important values you might need.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6bfb8691-d1db-4ddc-9d6d-d840f1ac88cb%2Fdcf94c74-e3cb-4a57-8148-b1e9b5088f93%2Fg8etd8ul_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Calculating Equilibrium Constants for Chemical Reactions**
**Introduction:**
In chemical thermodynamics, understanding the equilibrium constant is essential for predicting the concentrations of reactants and products in a chemical reaction at equilibrium. This topic explores the relationship between the equilibrium constants \( K_p \) and \( K_c \) and guides you through a calculation using the reaction of ammonium chloride.
**Problem Statement:**
The equilibrium constant, \( K_p \), for the given reaction is \( 1.04 \times 10^{-2} \) at \( 548 \, \text{K} \). You are required to calculate \( K_c \) for this reaction at the same temperature.
**Reaction:**
\[
\text{NH}_4\text{Cl(s)} \rightleftharpoons \text{NH}_3\text{(g)} + \text{HCl(g)}
\]
**Calculation:**
For the conversion between \( K_p \) and \( K_c \), use the formula:
\[
K_p = K_c(RT)^{\Delta n}
\]
where:
- \( \Delta n \) is the change in moles of gas (products - reactants).
- \( R \) is the ideal gas constant (\(0.0821 \, \text{L atm/mol K}\)).
- \( T \) is the temperature in Kelvin.
**Input Field:**
- \( K_c \) (Enter your calculated value here.)
**Submission:**
- Use the "Submit Answer" button to check your result.
- Use the "Retry Entire Group" if you need to attempt the calculation again.
**Note:**
Remember that \( \Delta n \) for the reaction is calculated from the gas moles. Here, \( \Delta n = 2 - 0 = 2 \).
Good luck with your calculation! Feel free to use the "References" link for any important values you might need.
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