The equilibrium constant, K, for the following reaction is 1.80×102 at 698 K. 2HI(g) H2(g) + 12(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.308 M HI, 4.14×102 M H2 and 4.14x102 M 12. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.199 mol of HI(g) is added to the flask? = M [HI] [H2]= [12] M M Σ Σ Σ

The equilibrium constant, K, for the following reaction is 1.80×102 at 698 K. 2HI(g) H2(g) + 12(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.308 M HI, 4.14×102 M H2 and 4.14x102 M 12. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.199 mol of HI(g) is added to the flask? = M [HI] [H2]= [12] M M Σ Σ Σ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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