The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I½(g) Calculate the equilibrium concentrations of reactant and products when 0.325 moles of HI are introduced into a 1.00 L vessel at 698 K. [HI] !i! [H2] = M [12] M
The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I½(g) Calculate the equilibrium concentrations of reactant and products when 0.325 moles of HI are introduced into a 1.00 L vessel at 698 K. [HI] !i! [H2] = M [12] M
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K.
2HI(g) H2(g) + I(g)
Calculate the equilibrium concentrations of reactant and products when 0.325 moles of HI are introduced into a 1.00 L vessel at 698 K.
[HI] =
M
[H2] =
M
[12]
M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F059e2b6a-3014-4b4b-8bf0-49c8d5e6302d%2F9512dc7a-fabb-4aaf-bed0-b650d5d9ffdc%2Ft4pucqr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K.
2HI(g) H2(g) + I(g)
Calculate the equilibrium concentrations of reactant and products when 0.325 moles of HI are introduced into a 1.00 L vessel at 698 K.
[HI] =
M
[H2] =
M
[12]
M
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