The equilibrium constant, K, for the following reaction is 1.04×10² at 548 K: NH,CI(s) NH3(g) + HCl(g) Calculate the equilibrium partial pressure of HCI when 0.480 moles of NH,CI(s) is introduced into a 1.00 L vessel at 548 K. PHCI = atm

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The equilibrium constant, K„, for the following reaction is 1.04×10² at 548 K:
NH,CI(s)
NH3(g) + HCI(g)
Calculate the equilibrium partial pressure of HCl when 0.480 moles of NH,Cl(s) is introduced into a 1.00 L vessel at 548 K.
PHCI =
atm
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Transcribed Image Text:Use the References to access important values if needed for this question. The equilibrium constant, K„, for the following reaction is 1.04×10² at 548 K: NH,CI(s) NH3(g) + HCI(g) Calculate the equilibrium partial pressure of HCl when 0.480 moles of NH,Cl(s) is introduced into a 1.00 L vessel at 548 K. PHCI = atm Submit Answer Retry Entire Group 4 more group attempts remaining Previous Next Email Instructor Save and
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Given data,Kp=1.04×10-2temperature=548KMoles of NH4Cl=0.480molesVolume of flask=1.00L

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