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The equilibrium constant in terms of pressures, Kp, for the reaction NH3(g) + HCl(g) NH4Cl(s) at 340 °C is 4.00. (a) If the partial pressure of ammonia is PNH, = 0.840 atm and solid ammonium chloride is present, what is the equilibrium partial pressure of hydrogen chloride at 340 °C? PHCI = atm

The equilibrium constant in terms of pressures, Kp, for the reaction NH3(g) + HCl(g) NH4Cl(s) at 340 °C is 4.00. (a) If the partial pressure of ammonia is PNH, = 0.840 atm and solid ammonium chloride is present, what is the equilibrium partial pressure of hydrogen chloride at 340 °C? PHCI = atm

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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The equilibrium constant in terms of pressures, Kp, for the reaction NH3(g) + HCl(g) 2NH4CI(S) at 340 °C is 4.00. (a) If the partial pressure of ammonia is PNH3 = 0.840 atm and solid ammonium chloride is present, what is the equilibrium partial pressure of hydrogen chloride at 340 °C? PHCI = (b) An excess of solid NH4Cl is added to a container filled with NH3 at 340 °C and a pressure of 1.34 atm. Calculate the pressures of NH3(9) and HCI(g) reached at equilibrium. PNH3 = atm PHCI = atm atm
Transcribed Image Text:The equilibrium constant in terms of pressures, Kp, for the reaction NH3(g) + HCl(g) 2NH4CI(S) at 340 °C is 4.00. (a) If the partial pressure of ammonia is PNH3 = 0.840 atm and solid ammonium chloride is present, what is the equilibrium partial pressure of hydrogen chloride at 340 °C? PHCI = (b) An excess of solid NH4Cl is added to a container filled with NH3 at 340 °C and a pressure of 1.34 atm. Calculate the pressures of NH3(9) and HCI(g) reached at equilibrium. PNH3 = atm PHCI = atm atm
The equilibrium constant in terms of pressures for the reduction of tungsten (VI) oxide to tungsten at 25 °C is Kp = 21.1, corresponding to the reaction WO3(s) + 3CO(g) 2W(s) + 3CO₂(g) If the total pressure of an equilibrium system at 25 °C is 2.96 atm, calculate the partial pressures of CO(g) and CO₂(g). Pco= PCO₂ atm atm
Transcribed Image Text:The equilibrium constant in terms of pressures for the reduction of tungsten (VI) oxide to tungsten at 25 °C is Kp = 21.1, corresponding to the reaction WO3(s) + 3CO(g) 2W(s) + 3CO₂(g) If the total pressure of an equilibrium system at 25 °C is 2.96 atm, calculate the partial pressures of CO(g) and CO₂(g). Pco= PCO₂ atm atm
Expert Solution
Step 1 Calculation of required value for the first equilibrium reaction

Given equilibrium reaction ;

                        NH3 (g)  +  HCl (g)  ⇔NH4Cl (s)

                         Kp of the reaction at 340 oC = 4.00

 (a)  Partial pressure of NH3 (pNH3) = 0.840 atm

       Now, the expression of Kp for the given equilibrium reaction is ;

                                     Kp=1pNH3×pHCl              ( Since NH4Cl is solid and so its fugacity is equal to unity)

                               ⇒ 4 = 10.840 ×pHCl

                               ⇒pHCl = 10.840 ×4

                               ⇒pHCl = 0.298 atm

Hence, the equilibrium partial pressure of hydrogen chloride at 340 oC is 0.298 atm

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