The equilibrium constant for the reaction below is Kc = 6.49xx10--2 at 439 K. 2СЗH6(g) 3D С2H4(9)+С4н8(g)2C3Н6 (g) — С2Н4(g)+ C4H8(g) In an experiment, 0.100 moles of each of C3H6, C2H4, and C4H8 are placed in a 1.0 L reaction vessel. What is the equilibrium concentration of C3H6 when the reaction above reaches equilibrium at 439 K?

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The equilibrium constant for the reaction below is
Kc = 6.49xx10¯-2 at 439 K.
2C3H6(g) = C2H4(g)+C4H8(g)2C3H6(g) = C2H4(g)+
C4H8(g)
In an experiment, 0.100 moles of each of C3H6,
C2H4, and C4H8 are placed in a 1.0 L reaction
vessel. What is the equilibrium concentration of
C3H6 when the reaction above reaches
equilibrium at 439 K?
---
Transcribed Image Text:The equilibrium constant for the reaction below is Kc = 6.49xx10¯-2 at 439 K. 2C3H6(g) = C2H4(g)+C4H8(g)2C3H6(g) = C2H4(g)+ C4H8(g) In an experiment, 0.100 moles of each of C3H6, C2H4, and C4H8 are placed in a 1.0 L reaction vessel. What is the equilibrium concentration of C3H6 when the reaction above reaches equilibrium at 439 K? ---
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