The equilibrium constant for the reaction A(g) + 2B(g) → 3C(g) is 12.3 at 975 K. a. Calculate the ∆G°, kJ/mol, for the reaction at the given temperature. b. Calculate the ∆G, kJ/mol, for the reaction when the concentrations are: [A] = 0.755 M, [B] = 0.600 M, and [C] = 0.250 M at the same temperature.
The equilibrium constant for the reaction A(g) + 2B(g) → 3C(g) is 12.3 at 975 K. a. Calculate the ∆G°, kJ/mol, for the reaction at the given temperature. b. Calculate the ∆G, kJ/mol, for the reaction when the concentrations are: [A] = 0.755 M, [B] = 0.600 M, and [C] = 0.250 M at the same temperature.
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The equilibrium constant for the reaction A(g) + 2B(g) → 3C(g) is 12.3 at 975 K.
a. Calculate the ∆G°, kJ/mol, for the reaction at the given temperature.
b. Calculate the ∆G, kJ/mol, for the reaction when the concentrations are: [A] = 0.755 M,
[B] = 0.600 M, and [C] = 0.250 M at the same temperature.
Expert Solution
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Step 1
The equilibrium reaction given is,
=> A (g) + 2 B(g) --------> 3 C (g) Keq = 12.3
Given : Temperature = 975 K
Step by step
Solved in 4 steps
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