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The equilibrium constant for the chemical equation N₂(g) + 3H₂(g)2NH₂(g) is Kp = 0.249 at 253 °C. Calculate the value of Ke for the reaction at 253 °C. Kc =

The equilibrium constant for the chemical equation N₂(g) + 3H₂(g)2NH₂(g) is Kp = 0.249 at 253 °C. Calculate the value of Ke for the reaction at 253 °C. Kc =

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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General Chemistry 4th Edition The equilibrium constant for the chemical equation N₂(g) + 3H₂(g)2NH₂(g) is Kp = 0.249 at 253 °C. Calculate the value of Ke for the reaction at 253 °C. Kc = O Search University presente
Transcribed Image Text:General Chemistry 4th Edition The equilibrium constant for the chemical equation N₂(g) + 3H₂(g)2NH₂(g) is Kp = 0.249 at 253 °C. Calculate the value of Ke for the reaction at 253 °C. Kc = O Search University presente
Macmillan Learning At a certain temperature, 0.980 mol SO, is placed in a 2.00 L container. 2 SO₂(g) 2 SO₂(g) + O₂(g) At equilibrium, 0.130 mol O₂ is present. Calculate Kc. Kc = O Search
Transcribed Image Text:Macmillan Learning At a certain temperature, 0.980 mol SO, is placed in a 2.00 L container. 2 SO₂(g) 2 SO₂(g) + O₂(g) At equilibrium, 0.130 mol O₂ is present. Calculate Kc. Kc = O Search
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Question -1

Given ->

N2(g) + 3H2(g) -----> 2NH3(g)   Kp= 0.249 

T = 253°C = 253 + 273 = 526 K 

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