the equilibrium constant at a temperature of 25 °C is determined to be K=603500. What can be concluded from this? Pick one: a) Since the value of the equilibrium constant is large, the reaction is fast b) The equilibrium of the reaction favors the reaction. However, it is not possible to be sure whether it is worth making ammonia using this method, because the reaction can be slow c) The reaction is spontaneous, but a large part of the starting material remains unreacted d) both enthalpy and entropy terms are favorable for the reaction
the equilibrium constant at a temperature of 25 °C is determined to be K=603500. What can be concluded from this? Pick one: a) Since the value of the equilibrium constant is large, the reaction is fast b) The equilibrium of the reaction favors the reaction. However, it is not possible to be sure whether it is worth making ammonia using this method, because the reaction can be slow c) The reaction is spontaneous, but a large part of the starting material remains unreacted d) both enthalpy and entropy terms are favorable for the reaction
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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the equilibrium constant at a temperature of 25 °C is determined to be K=603500. What can be concluded from this? Pick one:
a) Since the value of the equilibrium constant is large, the reaction is fast
b) The equilibrium of the reaction favors the reaction. However, it is not possible to be sure whether it is worth making ammonia using this method, because the reaction can be slow
c) The reaction is spontaneous, but a large part of the starting material remains unreacted
d) both enthalpy and entropy terms are favorable for the reaction
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