The equations re + uz – cos(v) – 2 = 0 and u cos(y) + 4r?v – 5yz2 – 1 = 0 can be solved for (u,v) as functions of (x.y.z) near the point P(xy.z.u.v)=(2,0,1,1,0). Find ()2.y at (2.0,1). (re + uz – cos(v) – 2 = 0 ve u cos(y) + 4au- 5yz? -1 0 denklemleri P(x.y,z,u.v)=(2,0,1,1,0) noktası civarında (xy.z)'nin fonksiyonu olmak üzere (u.v) için çözümlüdür. (2,0,1) noktasında ()zy yi hesaplayınız.) Lütfen birini seçin: 01 O 0,5 O-0,5 0-1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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The equations rey + uz
cos(v) – 2 = 0 and u cos(y) + 4r'v – 5yz? – 1= 0 can be solved for (u,v) as functions of (xy.z) near the point P(xy.zu.v)=(2,0,1,1,0). Find ()zy at
(2.0,1).
(re + uz – cos(v) – 2 = 0 ve u cos(y) + 4x?v – 5yz? – 1=0 denklemleri P(x.y.z,u.v)=(2,0,1,1,0) noktası civarında (xy.z)'nin fonksiyonu olmak üzere (u.v) için çözümlüdür. (2,0,1)
noktasında ()zy yi hesaplayınız.)
Lütfen birini seçin:
01
O 0,5
O-0,5
0-1
Transcribed Image Text:The equations rey + uz cos(v) – 2 = 0 and u cos(y) + 4r'v – 5yz? – 1= 0 can be solved for (u,v) as functions of (xy.z) near the point P(xy.zu.v)=(2,0,1,1,0). Find ()zy at (2.0,1). (re + uz – cos(v) – 2 = 0 ve u cos(y) + 4x?v – 5yz? – 1=0 denklemleri P(x.y.z,u.v)=(2,0,1,1,0) noktası civarında (xy.z)'nin fonksiyonu olmak üzere (u.v) için çözümlüdür. (2,0,1) noktasında ()zy yi hesaplayınız.) Lütfen birini seçin: 01 O 0,5 O-0,5 0-1
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