The equation y² = cx is the general solution of: y' = 2x y': %3D у 2y A y' = 2 2y y' = 2x O D B.

Q: Q.3 Solve v = e»+vã dx

A: Use the variable separable method and Integrate to get the solution of given differential equation.

Q: Solve the equation dy, 3y + dx +2 = 3x, y(1) = 1.

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Q: calculate y" and y"'. y = 7 − 2x

A: Given function: y=7-2x

Q: The equation y? = cx is the general solution of: A. y'= 2 В. у" C. y' = 2 D. y' = %3D 2x 2х %3D y 2y

A: From the given equation: y2=cx Now differentiate the given function with respect to x.…

Q: Solve dx/y-x = dy/y+x = zdz/x2-2xy-y2

A: Solve:dxy-x=dyy+x=zdzx2-2xy-y2

Q: Solve 2- (2xy - 2y)dx + (3x'y-4x)dy 0

A: We have to solve given problem:

Q: find sol. y'- y =y2e-x

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Q: uation: Solve the e * + 2xdy = 0. = x

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Q: Solve for y in two ways. y' - 5y = -3

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Q: 2x - 3y = 7 y = 3x – 7 .

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Q: Solve (3x*y? – x²)dy + (4x³y3 - 2xy)dx 0 %3D | | .3

A: Given differential equation is exact differential equation. We solve it as follows:

Q: find y' for Zy%3D2X-2y

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Q: 5. Solve: 4xy2(3x³y – 5xy) = 0, Let y = 2 %3D

A: A detailed solution is given below

Q: Find the solution. y'+ ty = ty3

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Q: Solve (1+xy)x dy + (1- xy)y dx 0. %3D

A: By using simple differential and integration

Q: Solve for the value of constant C in the equation: (2x + 3)y' = y + (2x + 3)¹/² when x = -1 and y =…

A: Given:- 2x+3y'=y+2x+31/2

Q: Calculate y" and y"'. y = x4 − 25x2 + 2x

A: Use the power rule and sum rule and difference rule of derivative:

Q: Solve (2xy-2xy- = 0 4xy² +2x) dx + (3x2y + 4y) dy %3D

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Q: х2 9 dy + sinx - у %3D0 dx

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Q: T= tan (x+2y+ 3Z) %3D Find: Txx XX Tx Txy Ty Tyy Tyx Tz Tzz Tzx T zy

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Q: Find oy for dx2

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Q: Solve y'+xy= xy“.

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Q: 1. Solve for 'x': vx + v2x +7 = 8

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Q: (x² – 9) + xy = 0 dx

A: We have to solve the differential equation x2-9 dydx + xy = 0

Q: 1. y = x3 – 2x² + 3x – 5 - - dy 3x2 – 4x + 3 - dx

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