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The equation used to predict annual cauliflower yield (in pounds per acre) is y = 24,321 +4.534x₁ - 4.671x2, where x₁ is the number of acres planted and X2 is the number of acres harvested. Use the multiple regression equation to predict the y-values for the values of the independent variables. (a) x₁ = 36,200, x2 = 36,500 (b) x₁ = 37,800, x₂ = 38,100 (c) x₁ = 38,900, x₂ = 39,000 (d) x₁ = 42,100, x2 = 42,200 (a) The predicted yield is 17960.3 pounds per acre. (Round to one decimal place as needed.). (b) The predicted yield is 17741.1 pounds per acre. (Round to one decimal place as needed.) (c) The predicted yield is 18524.6 pounds per acre. (Round to one decimal place as needed.) (d) The predicted yield is pounds per acre. (Round to one decimal place as needed.)

The equation used to predict annual cauliflower yield (in pounds per acre) is y = 24,321 +4.534x₁ - 4.671x2, where x₁ is the number of acres planted and X2 is the number of acres harvested. Use the multiple regression equation to predict the y-values for the values of the independent variables. (a) x₁ = 36,200, x2 = 36,500 (b) x₁ = 37,800, x₂ = 38,100 (c) x₁ = 38,900, x₂ = 39,000 (d) x₁ = 42,100, x2 = 42,200 (a) The predicted yield is 17960.3 pounds per acre. (Round to one decimal place as needed.). (b) The predicted yield is 17741.1 pounds per acre. (Round to one decimal place as needed.) (c) The predicted yield is 18524.6 pounds per acre. (Round to one decimal place as needed.) (d) The predicted yield is pounds per acre. (Round to one decimal place as needed.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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What is the answer to part d 

N The equation used to predict annual cauliflower yield (in pounds per acre) is y = 24,321 +4.534x₁ - 4.671x2, where x₁ is the number of acres planted and x₂ is the number of acres harvested. Use the multiple regression equation to predict the y-values for the values of the independent variables. (a) x₁ = 36,200, x₂ = 36,500 (b) x₁ = 37,800, x₂ = 38,100 (c) x₁ = 38,900, x₂ = 39,000 (d) x₁ = 42,100, x₂ = 42,200 (a) The predicted yield is 17960.3 pounds per acre. (Round to one decimal place as needed.) (b) The predicted yield is 17741.1 pounds per acre (Round to one decimal place as needed.) (c) The predicted yield is 18524.6 pounds per acre. (Round to one decimal place as needed.) (d) The predicted yield is pounds per acre (Round to one decimal place as needed.)
Transcribed Image Text:N The equation used to predict annual cauliflower yield (in pounds per acre) is y = 24,321 +4.534x₁ - 4.671x2, where x₁ is the number of acres planted and x₂ is the number of acres harvested. Use the multiple regression equation to predict the y-values for the values of the independent variables. (a) x₁ = 36,200, x₂ = 36,500 (b) x₁ = 37,800, x₂ = 38,100 (c) x₁ = 38,900, x₂ = 39,000 (d) x₁ = 42,100, x₂ = 42,200 (a) The predicted yield is 17960.3 pounds per acre. (Round to one decimal place as needed.) (b) The predicted yield is 17741.1 pounds per acre (Round to one decimal place as needed.) (c) The predicted yield is 18524.6 pounds per acre. (Round to one decimal place as needed.) (d) The predicted yield is pounds per acre (Round to one decimal place as needed.)
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