The equation resultant wave from the superposition of two waves propagating in opposite directions is: y = 0.25 sin (2nx) Cos (nt) The speed of propagation of the initial waves is: A-V = 0 m/sec, B- V = 2 m/sec, C-V = 0.5 m/sec, D-V = 0.25 a m/sec, E-V = 0.5 n m/sec,,

Question
The equation resultant wave from the superposition of two waves
propagating in opposite directions is: y = 0.25 sin (2nx) Cos (nt)
The speed of propagation of the initial waves is:
A-V = 0 m/sec,
B- V = 2 m/sec,
C-V = 0.5 m/sec,
D-V = 0.25 m/sec,
E-V = 0. 5 n m/sec,,
A
В
Ос
D
Transcribed Image Text:The equation resultant wave from the superposition of two waves propagating in opposite directions is: y = 0.25 sin (2nx) Cos (nt) The speed of propagation of the initial waves is: A-V = 0 m/sec, B- V = 2 m/sec, C-V = 0.5 m/sec, D-V = 0.25 m/sec, E-V = 0. 5 n m/sec,, A В Ос D
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