The equation of the tangent plane to the surface x2 at the point (-2, 1, 3) is Select one: +2y z-3 -2/3 1 −늘(x - 2) + 2(y + 1) - 룩(z + 3) = 0 -글(x + 2) + 2(y - 1) - 2(z - 3) = 0 - 글(x + 2) + 2(y - 1) - 룸(z - 3) = 을 x+2 == = = 3

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The equation of the tangent plane to the surface
x²
8
at the point (-2, 1, 3) is
Select one:
-1/2
None of them
+ 2y
-(x-2) + 2(y + 1) - (z + 3) = 0
-(x + 2) + 2(y-1)-(z − 3) = 0
-(x + 2) + 2(y-1)-(z − 3) = 2/1
= x=²=
=
z-3
-2/3
1
=
3
Transcribed Image Text:The equation of the tangent plane to the surface x² 8 at the point (-2, 1, 3) is Select one: -1/2 None of them + 2y -(x-2) + 2(y + 1) - (z + 3) = 0 -(x + 2) + 2(y-1)-(z − 3) = 0 -(x + 2) + 2(y-1)-(z − 3) = 2/1 = x=²= = z-3 -2/3 1 = 3
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