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The equation of OP is (x- 3)+ (y- 1)²=9. Without graphing, explain how you can determine whethen che point (4,-1) lies on OP, in the interior of OP, or in the exterior of OP. he pt. (select) v lie on the O because it (select) v a solution to the equation (x- 3)2 + (y– 1)2 = ince (4 – 3)2 + (-1– 1)2 (select) v 9, the pt. lies (select) OP. (select) in the exterior of on in the interior of

The equation of OP is (x- 3)+ (y- 1)²=9. Without graphing, explain how you can determine whethen che point (4,-1) lies on OP, in the interior of OP, or in the exterior of OP. he pt. (select) v lie on the O because it (select) v a solution to the equation (x- 3)2 + (y– 1)2 = ince (4 – 3)2 + (-1– 1)2 (select) v 9, the pt. lies (select) OP. (select) in the exterior of on in the interior of

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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The equation of OP is (x- 3) + (y- 1)=9. Without graphing, explain how you can determine whether the point (4,-1) lies on OP, in the interior of OP, or in the exterior of OP. The pt. (select) v lie on the O because it (select) v a solution to the equation (x- 3)2 + (y- 1)2 = 9. Since (4 – 3)2 + (-1– 1)2 (select) 9, the pt. lies (select) OP. (select) in the exterior of on in the interior of
Transcribed Image Text:The equation of OP is (x- 3) + (y- 1)=9. Without graphing, explain how you can determine whether the point (4,-1) lies on OP, in the interior of OP, or in the exterior of OP. The pt. (select) v lie on the O because it (select) v a solution to the equation (x- 3)2 + (y- 1)2 = 9. Since (4 – 3)2 + (-1– 1)2 (select) 9, the pt. lies (select) OP. (select) in the exterior of on in the interior of
The equation of OP is (x- 3)+(y- 1)=9. Without graphing, explain how you can determine whether the point (4,-1) lies on OP, in the interior of OP, or in the exterior of OP. The pt. (select) v lie on the O because it (select) v a solution to the equation (x- 3)2 + (y-1)2= 9. Since (4 – 3)2 + (-1- 1)2 (select) v 9, the pt. lies (select) OP. (select) A || V
Transcribed Image Text:The equation of OP is (x- 3)+(y- 1)=9. Without graphing, explain how you can determine whether the point (4,-1) lies on OP, in the interior of OP, or in the exterior of OP. The pt. (select) v lie on the O because it (select) v a solution to the equation (x- 3)2 + (y-1)2= 9. Since (4 – 3)2 + (-1- 1)2 (select) v 9, the pt. lies (select) OP. (select) A || V
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