The equation of displacement of particle performing SHM is x = 0.25 sin (200 t). The maximum velocity is %3D (a) 100 m/s (b) 200 m/s (c) 50 m/s (d) 150 m/s
The equation of displacement of particle performing SHM is x = 0.25 sin (200 t). The maximum velocity is %3D (a) 100 m/s (b) 200 m/s (c) 50 m/s (d) 150 m/s
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![The equation of displacement of particle
performing SHM is x = 0.25 sin (200 t). The
maximum velocity is
%3D
bne ()
200 m/s
(a)
100 m/s
(b)
50 m/s
(d)
150 m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F314a8e3a-eb1d-41a7-a759-93189948f0b0%2Fb2aafd6c-fd91-4e0f-8797-0569ec75cd90%2Fugoyvfp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The equation of displacement of particle
performing SHM is x = 0.25 sin (200 t). The
maximum velocity is
%3D
bne ()
200 m/s
(a)
100 m/s
(b)
50 m/s
(d)
150 m/s
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