The equation of a quartic function with zeros -5, 1, and 3 with an order 2 is: * O f(x) = k(x - 3)(x + 5)(x - 1)^2 O f(x) = k(x - 1)(x + 5)(x - 3)^2 O f(x) = k(x + 1)(x - 5)(x + 3)^2 O f(x) = k(x - 1)(x + 3)(x + 5)^2

Q: Determine the value of A such that the domain of f(x) = +14 is (-∞0,8) U (8,00) - A

A: The domain of a function is the set of input or argument values for which the function is real and…

Q: If ƒ (x) = x − 7 and g(x) = O(-∞, 4) 0 (-∞, 4] O (4,0) O [4,00) O (4,7) U (7, ∞0) what is the domain…

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Q: Solve the following function for the value (s) of x  2x2-6x+4=0 a)(2,0) (1,0) b)(-2,0) (1,0)…

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Q: find a so that the point (-1,4) is on the grapn of f(x) = ax² + 2

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Q: 1 and g(z) 4. f(x) = %3D

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Q: A quadratic polynomial y = 4x² + 7x – 3 has roots p and q. Find a quadratic g(x) = x² + ax + ß with…

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Q: Find f[g(x)] and g[f(x)]. f(x)=√√√x+2, g(x) = 18x² - 11 f[g(x)] = g[f(x)] =

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Q: The quadratic form Q(x) = 3x,² + 7x22 + 4x3? is (a) Positive definite (b) Indefinite (c) Negative…

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Q: Suppose f(x) = x + 3x + 1. In this problem, we will show that f has exactly one root (or zero) in…

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Q: 3) Let f(x) = and g(x) = 2 +x 1-3 x Compute and simplify (f g) (x), then state its domain.

A: Given: f(x)=x2+xg(x)=11-3x The objective is to find f∘g(x)

Q: Algebraically, find all zeros of f(x) = 8x3-6x2-36x + 27 in simplest form, %3D 4. Format Font - Size…

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Q: Given the function h (x) = 9x¹ - x² A) Factor: h(x)= [Select] B) Determine the real zeros: [Select]…

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Q: Write a cubic function whose graph passes through the given points. (4, 3) (-1, 0) (5, 0) -8 4 (2,…

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Q: The quadratic form X1 e x2 = x} – 2x1X2 + x} + x} %3D - X3 on 3 is Positive definite Positive…

A: The solution is given as

Q: f (x) = -3x2 + 3x – 3 and | x 9

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Q: Given f(x) = 2(x - 1)(x + 3)³(5x + 1)^(x − 3)¹ List the zeroes (ex. 4, 6, -2): Degree: End behavior:…

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Q: Find the composition f[g(x)] if: O 2-3u10 (10 - 15x2)5 O f(u) = u5 and g(x) = 2 - 3x² (2-3x²)²…

A: fu=u5 , gx=2-3x2

Roots

The main dissimilarity between real and complex roots is that the real roots are obtained as real numbers, in contrast with the complex roots, which are indicated as imaginary numbers. The standard format for depicting any complex number is in the form of a + bi.