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The equation f(x) = x3 – x2 – 10x – 8 has a root within the interval 3.8

The equation f(x) = x3 – x2 – 10x – 8 has a root within the interval 3.8

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The equation f(x) = x3 – x2 – 10x – 8 has a root within the interval 3.8 <x< 4.5. If the prespecified tolerance of 0.001 is required, find this root using both the Bisection and Newton-Raphson Method. Compare the rate of convergence on the root between the two methods. *--
Transcribed Image Text:The equation f(x) = x3 – x2 – 10x – 8 has a root within the interval 3.8 <x< 4.5. If the prespecified tolerance of 0.001 is required, find this root using both the Bisection and Newton-Raphson Method. Compare the rate of convergence on the root between the two methods. *--
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