The equation for ATP hydrolysis isH,0ATP - ADP + P,AG" - -30.5 kl/molCalculate AG for ATP hydrolysis to arrange the conditions from most favorable to least favorable. Assume a temperature of37.0 °C and R- 8.315 J(mol K).ATP hydrolysis most favorableATP hydrolysis least favorableAnswer Bankliver: [ATP] = 3.4 mM: (ADP) - 1.3 mM; (P) = 4.8 mMbrain: [ATP] = 2.6 mM; [ADP] = 0.7 mM: [P.] = 2.7 mM%3Dmuscle: [ATP] = 8.1 mM; [ADP] = 0.9 mM: [P.] = 8.1 mMCalculate AG for ATP hydrolysis in muscle at 20.0 °C. Use the muscle concentrations from the first question.AG =kJ/mol

ATP hydrolysis is most favourable in the brain and least favourable in liver . The detailed…

The equation for ATP hydrolysis is ATP ADP +P, AG" - -30.5 kimol Calculate AG for ATP hydroiysis to arrange the conditions from most favorable to least favorable. Assume a temperature of 37.0 °C and R- 8.315 J(mol - K). ATP hydrolysis most favorable ATP hydrolysis lecast favorable Answer Bank

The equation for ATP hydrolysis is ATP ADP +P, AG" - -30.5 kimol Calculate AG for ATP hydroiysis to arrange the conditions from most favorable to least favorable. Assume a temperature of 37.0 °C and R- 8.315 J(mol - K). ATP hydrolysis most favorable ATP hydrolysis lecast favorable Answer Bank

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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C(s) + 2H2(g) CH4(g) ΔH° = –75 kJ exo/endo - thermic Δν(gas) = __, (decrease)Vtot --> which way will equation shift? what will happen if there is an increase in: P(CH4) shift? __ ...two ways to to lose mass(C)? ___________ higher T shift? __
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ation provided. E Hydrogen, bromine, and HBr in the gas phase are in equilibrium in a container of fixed volume. H,(g) + Br,(g) 2 HBrg) AH=-103.7 kJ How will each of these changes affect the indicated quantities? Write "increase," "decrease," or "no change. Change DHB1 Some H, is added to the container. The temperature of the gases in the container is increased. The pressure of HBr is increased.
The equation for ATP hydrolysis is H₂O ATP→ ADP + P₁ AG"=-30.5 kJ/mol Calculate AG for ATP hydrolysis to arrange the conditions from most favorable to least favorable. A 37.0 °C and R = 8.315 J/(mol K). . ATP hydrolysis most favorable ATP hydrolysis least favorable Answer Bank muscle: [ATP] = 8.1 mM; [ADP] = 0.9 mM; [Pi] = 8.1 mM brain: [ATP] = 2.6 mM; [ADP] = 0.7 mM; [Pi] = 2.7 mM liver: [ATP] = 3.4 mM; [ADP] = 1.3 mM; [Pi] = 4.8 mM
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O ENTROPY AND FREE ENERGY Using reaction free energy to predict equilibrium composition D 3/5 Consider the following equilibrium: 2NOC1 (g) - 2NO (g)+ Cl, (g) AG" =41. kJ Now suppose a reaction vessel is filled with 2.68 atm of nitrosyl chloride (NOCI) and 3.74 atm of chlorine (Cl,) at 227. °C. Answer the following questions about this system: rise Under these conditions, will the pressure of Cl, tend to rise or fall? fall Is it possible to reverse this tendency by adding NO? In other words, if you said the pressure of Cl, will tend to rise, can that yes be changed to a tendency to fall by adding NO? Similarly, if you said the no pressure of Cl, will tend to fall, can that be changed to a tendency to rise by adding NO? If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO needed to reverse it. | atm Round your answer to 2 significant digits. II
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For the reaction 2HBr(g) + Cl₂ (g) → 2HCl(g) + Br₂ (g) AH = -81.1 kJ and AS° = -1.20 J/K The equilibrium constant for this reaction at 288.0 K is | Assume that ΔΗ° and AS are independent of temperature. Submit Answer Retry Entire Group 9 more group attempts remaining
< ✓ 11 Question 25 of 25 (1 point) | Question Attempt: 1 of 2 ✓ 12 ✓ 13 ✓ 14 Here are some facts about the reaction: ✓ 15 At -5.67 °C the concentration equilibrium constant K = 7.0 for a certain reaction. с • If the reaction is run at constant pressure, 101. kJ/mol of heat are absorbed. X 16 -1 1 • The constant pressure molar heat capacity C₂ = 2.23 J-mol K Р Using these facts, can you calculate Kat 9.4 °C? • If the reaction is run at constant pressure, the volume increases by 13.%. If you said yes, then enter your answer at right. Round it to 2 significant digits. If you said no, can you at least decide whether Kat 9.4 °C will be bigger or smaller than Kat -5.67 °C? O Yes. O No. 0 17 Yes, and K will be bigger. No. Yes, and K will be smaller.
M req For the reaction E 20 H₂(g) + Cl₂(g) → 2HCl(g) AH = -185 kJ and AS = 20.0 J/K The equilibrium constant for this reaction at 261.0 K is Assume that ΔΗ° and AS are independent of temperature. Submit Answer SA 4 000 000 R F Show Hint DE LO % 5 Retry Entire Group [Review Topics] [References] Use the References to access important values if needed for this question. T G Cengage Learning Cengage Technical Support < C 6 9 more group attempts remaining Y H & 7 U 8 J I 9 K 0 0 P Previous Next Email Instructor Save a +
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