The equation e^(8−6x) − 1 = 0 has a unique solution p = 4/3. Use Newton’s method with p0 = 1.332 to compute the next two approximations p1 and p2. If you apply Newton’s method with p0 = 2, what are p1 and p2? What comments can you make about the convergence of Newton’s method in general?

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A: Solution is as follows

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A: Solution