The equation 6x^3=43x^2+79x+30 is solved in the Summa of Luca Pacioli as follows: "Add the number to the cose to form a number, and then you get one cubo equal to 7 1/6 censi plus 18 1/6 , after you have reduced to one cubo [divided all the terms by 6]. Then divide the censi in half and multiply this half by itself, and add it onto the number. It will be 31 1/144 and the cosa is equal to the root of this plus 3 7/12 , which is half of censi." Show that Pacioli's answer is incorrect. What was he thinking of in presenting his rule?
The equation 6x^3=43x^2+79x+30 is solved in the Summa of Luca Pacioli as follows: "Add the number to the cose to form a number, and then you get one cubo equal to 7 1/6 censi plus 18 1/6 , after you have reduced to one cubo [divided all the terms by 6]. Then divide the censi in half and multiply this half by itself, and add it onto the number. It will be 31 1/144 and the cosa is equal to the root of this plus 3 7/12 , which is half of censi." Show that Pacioli's answer is incorrect. What was he thinking of in presenting his rule?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The equation 6x^3=43x^2+79x+30 is solved in the
Summa of Luca Pacioli as follows: "Add the number to
the cose to form a number, and then you get one cubo equal
to 7 1/6 censi plus 18 1/6 , after you have reduced to one cubo
[divided all the terms by 6]. Then divide the censi in half
and multiply this half by itself, and add it onto the number.
It will be 31 1/144 and the cosa is equal to the root of this plus 3 7/12 , which is half of censi." Show that Pacioli's answer is incorrect. What was he thinking of in presenting his rule?
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