The enthalpy changes when a strong acid is neutralized by strong base is –56.1 kJ/mol. If 135 mL of 0.250 M HI at 23.15°C is mixed with 145 mL of 0.500 M NaOH, also at 23.15°C, what is the maximum temperature reached by the resulting solution? (Assume that there is no heat loss to the container, that the specific heat of the final solution is 4.18 J/g•°C, and that the density of the final solution is that of water.) HI + NaOH ---> H20 + Nal D 34.57 °C D 24.77 °C D 32.35 °C 26.06 °C O 22.24 C

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Chapter5: Thermochemistry
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The enthalpy changes when a strong acid is neutralized by strong base is –56.1 kJ/mol. If
135 mL of 0.250 M HI at 23.15°C is mixed with 145 mL of 0.500 M NaOH, also at
23.15°C, what is the maximum temperature reached by the resulting solution? (Assume
that there is no heat loss to the container, that the specific heat of the final solution is 4.18
J/g.°C, and that the density of the final solution is that of water.) HI + NaOH ---> H2O + Nal
34.57 °C
) 24.77 °C
32.35 °C
26.06 °C
O 22.24 C
Transcribed Image Text:The enthalpy changes when a strong acid is neutralized by strong base is –56.1 kJ/mol. If 135 mL of 0.250 M HI at 23.15°C is mixed with 145 mL of 0.500 M NaOH, also at 23.15°C, what is the maximum temperature reached by the resulting solution? (Assume that there is no heat loss to the container, that the specific heat of the final solution is 4.18 J/g.°C, and that the density of the final solution is that of water.) HI + NaOH ---> H2O + Nal 34.57 °C ) 24.77 °C 32.35 °C 26.06 °C O 22.24 C
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