The enthalpy change for the reaction of hydrogen gas with oxygen to produce water is -484 kJ for the equation as written: 2H₂(g) + O₂(g) → 2H₂O(g) AH = - 484 kJ a. What is the enthalpy change per mole of water produced? kj/mol H₂O b. Is the reaction exothermic or endothermic as written? Oexothermic Oendothermic c. What would be the enthalpy change for the reverse of the given equation (that is, for the decomposition of H₂O into its constituent elements)? kj

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The enthalpy change for the reaction of hydrogen gas with oxygen to produce water is -484 kJ for the equation as written:
2H₂(g) + O₂(g) → 2H₂O(g) AH = -484 kJ
a. What is the enthalpy change per mole of water produced?
kJ/mol H₂O
b. Is the reaction exothermic or endothermic as written?
Oexothermic
Oendothermic
c. What would be the enthalpy change for the reverse of the given equation (that is, for the decomposition of H₂O into its
constituent elements)?
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Transcribed Image Text:The enthalpy change for the reaction of hydrogen gas with oxygen to produce water is -484 kJ for the equation as written: 2H₂(g) + O₂(g) → 2H₂O(g) AH = -484 kJ a. What is the enthalpy change per mole of water produced? kJ/mol H₂O b. Is the reaction exothermic or endothermic as written? Oexothermic Oendothermic c. What would be the enthalpy change for the reverse of the given equation (that is, for the decomposition of H₂O into its constituent elements)? Submit Answer kj Retry Entire Group Show Hint 9 more group attempts remaining Cengage Learning Cengage Technical Support Previous Next Save and Exit
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