The engineering constants for an orthotropic material are found to be Ej= 27.579 GPa E2=20.684 GPa E3=21.374 GPa V12 = 0.2 G12=41.368 GPa V23 = 0.4 G23=48.263 GPa V13 = 0.6 G31=13.790 GPa Find the stiffness matrix [C] and the compliance matrix [S] for the preceding orthotropic material.
The engineering constants for an orthotropic material are found to be Ej= 27.579 GPa E2=20.684 GPa E3=21.374 GPa V12 = 0.2 G12=41.368 GPa V23 = 0.4 G23=48.263 GPa V13 = 0.6 G31=13.790 GPa Find the stiffness matrix [C] and the compliance matrix [S] for the preceding orthotropic material.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![1) The engineering constants for an orthotropic material are found to be
Ej= 27.579 GPa
E2=20.684 GPa
E3=21.374 GPa
V12 = 0.2
G12=41.368 GPa
V23 = 0.4
G23=48.263 GPa
V13 = 0.6
G31=13.790 GPa
Find the stiffness matrix [C] and the compliance matrix [S] for the preceding orthotropic
material.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff9a48f1b-b27d-490d-b6ed-500edbbd0416%2Fa8586281-520d-4b26-91f3-cb26dde06bc1%2Fdk7nhi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1) The engineering constants for an orthotropic material are found to be
Ej= 27.579 GPa
E2=20.684 GPa
E3=21.374 GPa
V12 = 0.2
G12=41.368 GPa
V23 = 0.4
G23=48.263 GPa
V13 = 0.6
G31=13.790 GPa
Find the stiffness matrix [C] and the compliance matrix [S] for the preceding orthotropic
material.
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