The engineer of a passenger train traveling at 25.0 m/s sights a freight train whose caboose is 200 m ahead on the same track (Fig. P2.62). The freight train is traveling at 15.0 m/s in the same direction as the passenger train. The engineer of the passenger train immediately applies the brakes causing a constant acceleration of 0.100 m/s in a direction opposite to the train’s velocity, while the freight train continues with constant speed. Take x = 0 at the location of the front of the passenger train when the engineer applies the brakes.  (a) Will the cows nearby witness a collision?  (b) If so, where will it take place?  (c) On a single graph, sketch the positions of the front of the passenger train and the back of the freight train

College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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The engineer of a passenger train traveling at 25.0 m/s sights a freight train whose caboose is 200 m ahead on the same track (Fig. P2.62). The freight train is traveling at 15.0 m/s in the same direction as the passenger train. The engineer of the passenger train immediately applies the brakes causing a constant acceleration of 0.100 m/s in a direction opposite to the train’s velocity, while the freight train continues with constant speed. Take x = 0 at the location of the front of the passenger train when the engineer applies the brakes. 

(a) Will the cows nearby witness a collision? 

(b) If so, where will it take place? 

(c) On a single graph, sketch the positions of the front of the passenger train and the back of the freight train

Upr = 25.0 m/s
a = -0.100 m/s?
Vyr = 15.0 m/s
200 m
Transcribed Image Text:Upr = 25.0 m/s a = -0.100 m/s? Vyr = 15.0 m/s 200 m
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