The energy that can be extracted from a storage battery is always less than the energy that goes into it while it is being charged. Why?
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The energy that can be extracted from a storage battery is always
less than the energy that goes into it while it is being charged.
Why?
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- In the figure below, capacitor 1 (C₁ Q₂ C₁ = = (a) Find the final charge on each capacitor after a long time has passed. с C 30.0 μF) initially has a potential difference of 55.0 V and capacitor 2 (C₂ = 5.10 μF) has none. The switches are then closed simultaneously. (b) Calculate the percentage of the initial stored energy that was lost when the switches were closed. %(22%) Problem 6: An air-filled capacitor has capacitance Co. When it is connected to a battery with EMF Vo it has charge Qo and stored energy Uo. Once the capacitor has charged, then the switch is opened, and finally a slab of material with dielectric constant K is inserted into the gap. -Vo + Vo d DV 20% Part (a) Which of the following physical quantities does not change when the dielectric material is inserted? Grade = 100% Correct Answver Student Final Submission Feedback Not available until end date The charge stored on the capacitor plates. Correct! Grade Summary Deduction for Final Submission 0% Deductions for Incorrect Submissions, Hints and Feedback [?] 0% Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displaved in Eastern Standard Time.Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 27, 2021 7:44 PM The charge stored on the capacitor plates. E * 20% Part (b) Enter an expression for the potential difference between…An electrical technician requires a capacitance of 2 µF in a circuit across a potential difference of 1 kV. A large number of 1 µF capacitors are available to him each of which can withstand a potential difference of not more than 400 V. Suggest a possible arrangement that requires the minimum number of capacitors.
- In open heart surgery, a much smaller amount of energy will defibrillate the heart. (a) What voltage is applied to the 8 μF capacitor of a heart defibrillator that stores 44 J of energy? V = kV (b) Find the amount of stored charge in mC. mC = Think & Prepare: The heart defibrillator consists of what electrical component?(2.) A positive charge of 11 microCoulombs and mass 2 grams is placed next to the positive plate of a capacitor. The voltage across the capacitor is 12 Volts. How fast is the charge moving when it hits the negative plate?(a) On a particular day, it takes 9.60×103 J of electric energy to start a truck’s engine. Calculate the capacitance of a capacitor that could store that amount of energy at 12.0 V.(b) What is unreasonable about this result? (c) Which assumptions are responsible?
- (13%) Problem 3: A neuron is a body cell that functions to create and transmit electrical signals. To do this, it uses chemical processes to maintain an electrical potential difference across its cell membrane. In this problem we will use our knowledge of electrical relationships to estimate the amount of charge on the membrane. Neurons come in a range of sizes, but a typical one may have a cell body of 20 µm (2 x 105 m) across. The thickness of the membrane is the same for most neurons - about 5 nm (5 x 109 m). The potential difference across a resting nerve membrane is about 70 mV (70 x 103 V). We'll model a piece of the cell membrane 10 μm x 10 μm across as a pair of infinite parallel plates separated by a distance d = 5 nm, with one plate representing the inner edge of the membrane and the other representing the outer edge of the membrane. A25% Part (a) Assuming the space separating the two plates of our membrane is empty space, calculate the electric field between the plates in…(a) On a particular day, it takes 9.60 × 103 J of electrical energy to start a truck’s engine. Calculate the capacitance of a capacitor that could store that amount of energy at 12.0 V. (b) What is unreasonable about this result? (c) Which assumptions are responsible?# 10. When a light bulb is connected in series to a battery and a capacitor, which of the following will happen: A) The bulb will not light up. B) The bulb will slowly start to light up, get brighter, and then stay brightly lit. C) The bulb will start brightly lit then will dim and go dark over a short period of time. D) The bulb will start brightly lit and stay brightly lit. O A O B D O C