Problem 3.42 - Enhanced - with Feedback(see the table).Specific Heats for Some SubstancesSubstanceElementsAluminuim, Al(s)Copper, Cu(s)Gold, Au(s)Iron, Fe(s)Silver, Ag(s)Titanium, Ti(s)CompoundsAmmonia, NH3(g)Ethanol, C₂H5OH(1)Sodium chloride,NaCl(s)Water, H₂O(1)Water, H₂O(s)3E$Rcal/g °C J/g °CD F0.214 0.8970.09200.3850.03080.1290.108 0.4520.0562 0.2350.125 0.5230.4882.040.588 2.460.207 0.8641.000.4854.1842.03HGF6Q Search▼Submit Request AnswerF7Part Dthe energy lost when 79.9 g of water cools from 86.4 °C to 3.2 °CSubmitPart ECopyright © 2023 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | CASUSΑΣΦF8Request Answerthe enerov needed to heat 12 6 of silver from 112 °C to 275 °CPearsonJFO?F10calF11F12ReviPrt Sc

We have to use the formula- Q=mc∆Twhere m=mass(g)C=heat capacity(calgoC)∆T=Temp changeQ=energy(cal)

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the energy lost when 79.9 g of water cools from 86.4 °C to 3.2 °C

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Problem 3.42 - Enhanced - with Feedback
(see the table).
Specific Heats for Some Substances
Substance
Elements
Aluminuim, Al(s)
Copper, Cu(s)
Gold, Au(s)
Iron, Fe(s)
Silver, Ag(s)
Titanium, Ti(s)
Compounds
Ammonia, NH3(g)
Ethanol, C₂H5OH(1)
Sodium chloride,
NaCl(s)
Water, H₂O(1)
Water, H₂O(s)
3
E
$
R
cal/g °C J/g °C
D F
0.214 0.897
0.0920
0.385
0.0308
0.129
0.108 0.452
0.0562 0.235
0.125 0.523
0.488
2.04
0.588 2.46
0.207 0.864
1.00
0.485
4.184
2.03
H
G
F6
Q Search
▼
Submit Request Answer
F7
Part D
the energy lost when 79.9 g of water cools from 86.4 °C to 3.2 °C
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Part E
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the enerov needed to heat 12 6 of silver from 112 °C to 275 °C
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J
FO
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F10
cal
F11
F12
Revi
Prt Sc

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