The energy arriving in 4 seconds on a detector having a surface of 2 m², and which is arranged perpendicular to the direction of propa gation of the light coming from a distant source is approximately 4.8 x 10 J. Find the module of the Poynting vector. ○ (to)S=0.6 x 10°J/m²s O (b)S=0.6 x 10¯³J/m²s O (S = 0.3 x 10 ®J/m²s O (S = 0.3 x 10J/m²s
The energy arriving in 4 seconds on a detector having a surface of 2 m², and which is arranged perpendicular to the direction of propa gation of the light coming from a distant source is approximately 4.8 x 10 J. Find the module of the Poynting vector. ○ (to)S=0.6 x 10°J/m²s O (b)S=0.6 x 10¯³J/m²s O (S = 0.3 x 10 ®J/m²s O (S = 0.3 x 10J/m²s
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Transcribed Image Text:The energy arriving in 4 seconds on a detector having a s
gia surface of 2 m², and which is arranged perpendicular to the direction of propa
gation of the light coming from a distant source, is approximately 4.8 x 10 J. Find the module of the Poynting vector.
O (to)S=0.6 x 10¯°J/m²s
(b)S=0.6 x 10¯³J/m²s
O (S = 0.3 x 10³J/m²s
O (S = 0.3 x 10¯ºJ/m²s
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