The empirical formula of the compound is

Chemistry: Matter and Change
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ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter11: Stoichiometry
Section: Chapter Questions
Problem 115A
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QUESTION 18
An analysis of a compound is performed. Percent by mass is
C 40.0% H 6.7% O 53.3%
The empirical formula of the compound is
O A. CH20
B. CHO2
C.C2HO
D. C2HO2
O E. CAHO3
QUESTION 19
_C2H4 +_ 02 = _CO2+_H2o
%3D
When the above equation is correctly balanced, the sum of the coefficients is
O A.8 OB.5 OC7 OD 6
Transcribed Image Text:QUESTION 18 An analysis of a compound is performed. Percent by mass is C 40.0% H 6.7% O 53.3% The empirical formula of the compound is O A. CH20 B. CHO2 C.C2HO D. C2HO2 O E. CAHO3 QUESTION 19 _C2H4 +_ 02 = _CO2+_H2o %3D When the above equation is correctly balanced, the sum of the coefficients is O A.8 OB.5 OC7 OD 6
QUESTION 20
When an aluminum atom forms an Al3* ion, the atom
O A. gains three protons
O B. gains two electrons and loses one proton
O C. loses three electrons
O D. gains three electrons
O E loses three protons
Transcribed Image Text:QUESTION 20 When an aluminum atom forms an Al3* ion, the atom O A. gains three protons O B. gains two electrons and loses one proton O C. loses three electrons O D. gains three electrons O E loses three protons
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