The elementary reaction   2H2O(g)↽−−⇀2H2(g)+O2(g)2H2O(g)↽−−⇀2H2(g)+O2(g)   proceeds at a certain temperature until the partial pressures of H2O,H2O, H2,H2, and O2O2 reach 0.0900 atm,0.0900 atm, 0.00250 atm,0.00250 atm, and 0.00650 atm,0.00650 atm, respectively. What is the value of the equilibrium constant at this temperature?

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The elementary reaction

 

2H2O(g)↽−−⇀2H2(g)+O2(g)2H2O(g)↽−−⇀2H2(g)+O2(g)

 

proceeds at a certain temperature until the partial pressures of H2O,H2O, H2,H2, and O2O2 reach 0.0900 atm,0.0900 atm, 0.00250 atm,0.00250 atm, and 0.00650 atm,0.00650 atm, respectively. What is the value of the equilibrium constant at this temperature?

Expert Solution
Step 1

The equilibrium reaction is as follows:            

2H2O(g)  2H2(g) +O2(g)

The partial pressure of H2O at equilibrium = 0.0900 atm

The partial pressure of H2 at equilibrium= 0.00250 atm

The partial pressure of O2 at equilibrium= 0.00650 atm

The equilibrium constant for the reaction is written as follows:

Kp=PH22×PO2PH2O2

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