The elementary matrices in sequential order that converted a coefficient matrix, A of a system of linear equations into an identity matrix are shown below. [1 0 0] 1 0, E3 1l 1 1 01 1 E1 -0.25 1 , E, = 10 -0.5 0 Lo -1.2 11 [1 0 = 0 1 0.4861, E5 E4 Lo o [1 0 -0.8333] [1 , E6 Lo 0.8 01 이1 11 = 10 1 = 10 1 lo o 1 [1 0 [0.25 0 0] 0, Eg 0 1] 01 = 0 0.8 0, Eg Lo E, = 1 = 10 1 Lo o 0.2778] The inverse of the coefficient matrix, A is: 0.2222 0.3333 |-0.2778 0.3333 -0.1111] 0.3889 0.0556 -0.3334 0.2778 0.2222 0.3333 -0.1111] |-0.2778 -0.0556 -0.3334 0.3333 0.3889 0.2778 0.2222 0.3333 -0.1111] -0.2778 0.3333 -0.3889 -0.0556 -0.3334 0.2778 0.2222 0.3333 -0.1111] Correct Answer:-0.2778 0.3333 0.3889 -0.0556 -0.3334 0.2778 0.2222 -0.3333 -0.1111] |-0.2778 0.3333 0.3889 -0.0556 -0.3334 0.2778
The elementary matrices in sequential order that converted a coefficient matrix, A of a system of linear equations into an identity matrix are shown below. [1 0 0] 1 0, E3 1l 1 1 01 1 E1 -0.25 1 , E, = 10 -0.5 0 Lo -1.2 11 [1 0 = 0 1 0.4861, E5 E4 Lo o [1 0 -0.8333] [1 , E6 Lo 0.8 01 이1 11 = 10 1 = 10 1 lo o 1 [1 0 [0.25 0 0] 0, Eg 0 1] 01 = 0 0.8 0, Eg Lo E, = 1 = 10 1 Lo o 0.2778] The inverse of the coefficient matrix, A is: 0.2222 0.3333 |-0.2778 0.3333 -0.1111] 0.3889 0.0556 -0.3334 0.2778 0.2222 0.3333 -0.1111] |-0.2778 -0.0556 -0.3334 0.3333 0.3889 0.2778 0.2222 0.3333 -0.1111] -0.2778 0.3333 -0.3889 -0.0556 -0.3334 0.2778 0.2222 0.3333 -0.1111] Correct Answer:-0.2778 0.3333 0.3889 -0.0556 -0.3334 0.2778 0.2222 -0.3333 -0.1111] |-0.2778 0.3333 0.3889 -0.0556 -0.3334 0.2778
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![The elementary matrices in sequential order that converted a coefficient matrix,
A of a system of linear equations into an identity matrix are shown below.
[1
0 0]
1 0, E3
1l
1
1
01
1
E1
-0.25 1
, E,
= 10
-0.5 0
Lo -1.2 11
[1 0
= 0 1 0.4861, E5
E4
Lo o
[1 0
-0.8333]
[1
, E6
Lo
0.8 01
이1
11
= 10 1
= 10
1
lo o
1
[1 0
[0.25 0 0]
0, Eg
0 1]
01
= 0 0.8 0, Eg
Lo
E, =
1
= 10 1
Lo o 0.2778]
The inverse of the coefficient matrix, A is:
0.2222
0.3333
|-0.2778 0.3333
-0.1111]
0.3889
0.0556
-0.3334
0.2778
0.2222
0.3333
-0.1111]
|-0.2778
-0.0556 -0.3334
0.3333
0.3889
0.2778
0.2222
0.3333
-0.1111]
-0.2778
0.3333
-0.3889
-0.0556 -0.3334
0.2778
0.2222
0.3333
-0.1111]
Correct Answer:-0.2778
0.3333
0.3889
-0.0556 -0.3334
0.2778
0.2222
-0.3333 -0.1111]
|-0.2778
0.3333
0.3889
-0.0556 -0.3334
0.2778](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6128a30d-be3c-4f5f-a17a-54eaa3ca9284%2F968f4ec1-0a0d-4660-aa18-7662f19df312%2Fra4wfe_processed.png&w=3840&q=75)
Transcribed Image Text:The elementary matrices in sequential order that converted a coefficient matrix,
A of a system of linear equations into an identity matrix are shown below.
[1
0 0]
1 0, E3
1l
1
1
01
1
E1
-0.25 1
, E,
= 10
-0.5 0
Lo -1.2 11
[1 0
= 0 1 0.4861, E5
E4
Lo o
[1 0
-0.8333]
[1
, E6
Lo
0.8 01
이1
11
= 10 1
= 10
1
lo o
1
[1 0
[0.25 0 0]
0, Eg
0 1]
01
= 0 0.8 0, Eg
Lo
E, =
1
= 10 1
Lo o 0.2778]
The inverse of the coefficient matrix, A is:
0.2222
0.3333
|-0.2778 0.3333
-0.1111]
0.3889
0.0556
-0.3334
0.2778
0.2222
0.3333
-0.1111]
|-0.2778
-0.0556 -0.3334
0.3333
0.3889
0.2778
0.2222
0.3333
-0.1111]
-0.2778
0.3333
-0.3889
-0.0556 -0.3334
0.2778
0.2222
0.3333
-0.1111]
Correct Answer:-0.2778
0.3333
0.3889
-0.0556 -0.3334
0.2778
0.2222
-0.3333 -0.1111]
|-0.2778
0.3333
0.3889
-0.0556 -0.3334
0.2778
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