The electron in a hydrogen atom falls from an excited energy level to the ground state in two steps, causing the emission of photons with wavelengths of 93.79 nm and 7503.1 nm, respectively. What is the principal quantum number of the initial excited energy level from which the electron falls?

icon
Related questions
Question
The electron in a hydrogen atom falls from an excited energy level to the ground state in two steps,
causing the emission of photons with wavelengths of 93.79 nm and 7503.1 nm, respectively. What is
the principal quantum number of the initial excited energy level from which the electron falls?
Transcribed Image Text:The electron in a hydrogen atom falls from an excited energy level to the ground state in two steps, causing the emission of photons with wavelengths of 93.79 nm and 7503.1 nm, respectively. What is the principal quantum number of the initial excited energy level from which the electron falls?
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 3 images

Blurred answer
Similar questions