The electric power P drawn from a generator by a lightbulb of resistance R is P = V2/R, where V is the line voltage. The resistance of bulb B is 87% greater than the resistance of bulb A. What is the ratio PB/PA of the power drawn by bulb B to the power drawn by bulb A if the line voltages are the same?

An Introduction to Physical Science
14th Edition
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Chapter1: Measurement
Section: Chapter Questions
Problem 2E
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The electric power P drawn from a generator by a lightbulb of resistance R is P = V2/R, where V is the line voltage. The resistance of bulb B is 87% greater than the resistance of bulb A. What is the ratio PB/PA of the power drawn by bulb B to the power drawn by bulb A if the line voltages are the same?

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