The electric field between two parallel plates connected to a 45 Volt battery is 1300 V/m. How far apart are the plates?
Q: A voltmeter indicates that the electric potential difference between two plates is 70.0 V. The…
A: Given data: Potential difference (ΔV) = 70.0 V Distance between plates (d) = 4.00 cm Required:…
Q: How far apart are two conducting plates that have an electric field strength of 9.22 x 103 V/m…
A: Given: The strength of the electric field in between the plates is 9.22x103 V/m. The potential…
Q: What is the strength of the electric field between two large parallel conducting plates separated by…
A:
Q: A doubly charged ion is accelerated to an energy of 37.0 keV by the electric field between two…
A: Energy, E = 37.0 keV = 37×10³×1.6×10-19 J = 5.92×10-15 JSeparation, d = 1.50 cm = 0.015 m
Q: 15. The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50…
A:
Q: Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero…
A: Given: The potential at a distance d = 8.00 cm from the zero volt plate (and 2.00 cm from the other)…
Q: Two metal plates are connected to a battery that holds the plates a fixed potential difference of…
A: Let's represent the electric field by the letter 'E' and the distance between the plates (path…
Q: The electric field between two parallel plates is 1900 V/m. The potential difference between the…
A:
Q: Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero…
A: Given, Separation between the plate d=10 cm =0.1 m Potential at a distance d'=8.05 cm = 0.085 m is…
Q: nd the maximum potential difference between two parallel conducting plates separated by 0.550 cm of…
A: 1)GivenDistance between two parallel plates (d)=0.550 cmd=0.550×10-2 mElectric field strenght…
Q: What is the strength (in V/m) of the electric field between two parallel conducting plates separated…
A:
Q: Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero…
A: Separation between parallel plates is One plate is at zero volts, that is, Voltage at a distance…
Q: Will the electric field strength between two parallel conducting plates exceed the breakdown…
A:
Q: A student is trying to build a home-made capacitor. He uses two 1.0 cm x 1.0 cm aluminum foil as the…
A:
Q: The capacitor is a parallel plate capacitor with a vacuum between the square plates. What is the…
A: The expression for the capacitance of parallel-plate capacitor is as follows: C=Aε0dA=Cdε0…
Q: Two plates separated by a distance d = 14.3 mm are charged to a potential difference V = 7.25 V. A…
A: Separation distance between the plates, d = 14.3 mm = 0.0143 mPotential difference, V = 7.25 VForce,…
Q: The electric field strength between two parallel conducting plates separated by 4.40 cm is 8.00 x…
A: Required : The potential difference.
Q: ideal parallel plate capacitor has square plates with side lengths of 0.1 m. the plates are spaced 2…
A:
Q: Two parallel plates, each having area A = 2706 cm2 are connected to the terminals of a battery of…
A:
Q: The electric field strength between two parallel conducting plates separated by 10.00 cm is 7.50×104…
A:
Q: A nervous physicist worries that the two metal shelves of his wood frame bookcase might obtain a…
A: Area A = 0.375 m2 separation is d = 0.175 m
Q: A potential difference of 2-V is applied between two large parallel metal plates separated by a…
A: Write the given values with the suitable variables. V=2 Vd=2 mm=2×10-3 m Here, V is the potential…
Q: An electron is fired at a speed v0 =4.30x106 m/s and at an angle θ0 = −45° between two parallel…
A: Velocity of the electron is v0 =4.30x106 m/s Distance between the plates is D = 5 mm Potential…
Q: A uniform electric field 1200 V/m is directed to the right. You (the agent) move a 2.5 µC charge 4…
A: Given , electric field ,E = 1200 V/m towards right. charge , q = 2.5μC Distance moved ,d = 4m…
Q: A student is trying to build a home-made capacitor. He uses two 1.0 cm x 1.0 cm aluminum foil as the…
A:
Q: An electron is to be accelerated in a uniform electric field having a strength of 0.5 x 106 V/m.…
A: Given :E=0.5 x 106 V/md=0.400 m
Q: The electric field in the region between the plates of a parallel plate capacitor has a magnitude of…
A: Given: In this question, the given details are, The electric field in the region between the plates…
Q: A small particle with a charge of 6.48 uC is initially moving at 55.0 m/s. It is then accelerated…
A: Given value --- charge = 6.48 micro C potential difference = 530 V. We have to find--- How much…
Q: Consider the electric field that has strength of 2.7×106 V/m. Find the maximum potential difference…
A: The given data are: E=2.7×106 V/md=6 cm=0.06 m Here, E denotes the electric field strength and d…
Q: a parallel plate capacitor is holding 10 C of charge while exposed to a 2V potential difference .…
A: In case of a parallel plate capacitor the energy depends on the charge stored and applied potential…
Q: A 10μμF capacitor charged to 2.0 kV and a 30μμF capacitor charged to 3.0 kV are connected to each…
A: C1 = 10μF V1 = 2000 volts C2 = 30μF V2 = 3000 volts
Q: The electric field between the plates of a paper-separated (K=3.75)(K=3.75) capacitor is 8.18×104…
A: Here, we have to obtain the capacitance and area of each plate.
Q: What is the magnitude, in volts, of the maximum potential difference between two parallel conducting…
A: Given: The strength of the electric field is 3x106 V/m. The separation between plates is 0.51 cm.
Q: What is the magnitude of an electric field between two parallel plates separated by 4.0 mm if the…
A: The magnitude of the electric field E between two parallel plates can be calculated using the…
Q: An electron in an x-ray machine is accelerated through a potential difference of 1.0 × 104 V before…
A: We know that∆K.E=-QVHere∆K.E=Change in kinetic energyQ=ChargeV=Potential Difference
The electric field between two parallel plates connected to a 45 Volt battery is 1300 V/m. How far apart are the plates?
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
