The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft2). An article gave the accompanying data on tank temperature (x) and efficiency ratio (y). Temp. 171 172 173 174 174 175 176 177 180 180 180 180 Ratio 0.84 1.30 1.43 1.03 1.07 1.08 1.04 1.80 1.45 1.60 1.61 2.13 stem (a) Construct a stem-and-leaf display of temperature. (Split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.) 17 17 17 17 17 Temp. 181 181 181 182 182 182 182 184 184 185 186 188 Ratio 2.15 0.85 1.43 0.90 1.81 1.94 2.68 1.49 2.52 3.00 1.87 3.08 18 18. 18 18 LAUSE SALT 18 leaf Comment on interesting features. The distribution is ---Select--- B and the variation is ---Select--- Construct a stem-and-leaf display of efficiency ratio. (Trucate the hundredths digit and split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.)
The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft2). An article gave the accompanying data on tank temperature (x) and efficiency ratio (y). Temp. 171 172 173 174 174 175 176 177 180 180 180 180 Ratio 0.84 1.30 1.43 1.03 1.07 1.08 1.04 1.80 1.45 1.60 1.61 2.13 stem (a) Construct a stem-and-leaf display of temperature. (Split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.) 17 17 17 17 17 Temp. 181 181 181 182 182 182 182 184 184 185 186 188 Ratio 2.15 0.85 1.43 0.90 1.81 1.94 2.68 1.49 2.52 3.00 1.87 3.08 18 18. 18 18 LAUSE SALT 18 leaf Comment on interesting features. The distribution is ---Select--- B and the variation is ---Select--- Construct a stem-and-leaf display of efficiency ratio. (Trucate the hundredths digit and split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft2). An article gave the accompanying data on
tank temperature (x) and efficiency ratio (y).
(a)
stem
17
Construct a stem-and-leaf display of temperature. (Split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter numbers from smallest to largest
separated by spaces. Enter NONE for stems with no values.)
17
17
17
Temp. 171 172 173 174 174 175 176 177 180 180 180 180
Ratio 0.84 1.30 1.43 1.03 1.07 1.08 1.04 1.80 1.45 1.60 1.61 2.13
17
Temp. 181 181 181 182 182 182 182 184 184 185 186 188
Ratio 2.15 0.85 1.43 0.90 1.81 1.94 2.68 1.49 2.52 3.00 1.87 3.08
18
18
18
18
USE SALT
18
leaf
Comment on interesting features.
The distribution is ---Select---
B and the variation is ---Select---
Construct a stem-and-leaf display of efficiency ratio. (Trucate the hundredths digit and split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter
numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F379782e3-36e2-4b06-9a33-e2601af30423%2F8d09ca40-9d8d-4e2c-89e8-56c3e4c33898%2Fxbpi9f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft2). An article gave the accompanying data on
tank temperature (x) and efficiency ratio (y).
(a)
stem
17
Construct a stem-and-leaf display of temperature. (Split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter numbers from smallest to largest
separated by spaces. Enter NONE for stems with no values.)
17
17
17
Temp. 171 172 173 174 174 175 176 177 180 180 180 180
Ratio 0.84 1.30 1.43 1.03 1.07 1.08 1.04 1.80 1.45 1.60 1.61 2.13
17
Temp. 181 181 181 182 182 182 182 184 184 185 186 188
Ratio 2.15 0.85 1.43 0.90 1.81 1.94 2.68 1.49 2.52 3.00 1.87 3.08
18
18
18
18
USE SALT
18
leaf
Comment on interesting features.
The distribution is ---Select---
B and the variation is ---Select---
Construct a stem-and-leaf display of efficiency ratio. (Trucate the hundredths digit and split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter
numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.)
![Comment on interesting features.
The distribution is ---Select---
e and the variation is ---Select--- .
Construct a stem-and-leaf display of efficiency ratio. (Trucate the hundredths digit and split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter
numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.)
stem
2
2
2
1
2
2
3
3
1
1
1
0
1
18
18
0
0
0
0
leaf](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F379782e3-36e2-4b06-9a33-e2601af30423%2F8d09ca40-9d8d-4e2c-89e8-56c3e4c33898%2F8yqzkxp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Comment on interesting features.
The distribution is ---Select---
e and the variation is ---Select--- .
Construct a stem-and-leaf display of efficiency ratio. (Trucate the hundredths digit and split the stems, placing leaves 0 to 1 on the first stem, leaves 2 to 3 on the second stem, etc. Enter
numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.)
stem
2
2
2
1
2
2
3
3
1
1
1
0
1
18
18
0
0
0
0
leaf
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