the E°cell is 0.194V, I could not get the rest of them right, plz show the full steps with calculations, thx a lot 2103 (aq) + 12H*(aq) + 10e = l2(s) + 6H20(1) E° = 1.195 V ClO4 (aq) + 8H*(aq) + 8e= CI (aq) + 4H20(1) E° = 1.389 V Consider the electrochemical cell where one of the half cells is comprised of a Pt electrode in a solution containing 103 (aq) at a concentration of 2.27 M and I2(s) with a H* concentration of 3.02 M. The other half cell is comprised of a Pt electrode in a solution containing CIO4 (aq) at a concentration of 6.00 M and CI (aq) at a concentration of 5.87 × 10-4 M with a H* concentration of 3.30 x 10-5 M. The temperature of the cell is 308.1 K. (a) What is Ecell (in V)? Report your answer to three decimal places in standard notation (b) Which one of the following chemical reactions describes the process occurring in the electrochemical cell? 412(s) + 5CIO4 (aq) + 4H20(1) → 81O3 (aq) + 5CI (aq) + 8H*(aq) 24103 (aq) + 10CI"(aq) + 24H*(aq) → 8l2(s) + 10CIO4 (aq) 8103 (aq) + 5CI (aq) + 8H*(aq) → 412(s) + 5CIO4 (aq) +. - 4H20(1) 812(s) + 10CIO4 (aq) → 24103 (aq) + 10CI (aq) + 24H*(aq) (c) What is AG (in kJ/mol)? Report your answer to three significant figures in scientific notation

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the E°cell is 0.194V, I could not get the rest of them right, plz show the full steps with calculations, thx a
lot
2103 (aq) + 12H*(aq) + 10e¯ = 12(s) + 6H20(1)
E° = 1.195 V
clo4 (aq) + 8H*(aq) + 8e = CI (aq) + 4H2O(1)
E° = 1.389 V
Consider the electrochemical cell where one of the half cells is comprised of a Pt electrode in a solution
containing 103 (aq) at a concentration of 2.27 M and I2(s) with a H* concentration of 3.02 M. The other
half cell is comprised of a Pt electrode in a solution containing CIO4 (aq) at a concentration of 6.00 M
and CI (aq) at a concentration of 5.87 x 10-4 M with a H* concentration of 3.30 x 10-5 M. The
temperature of the cell is 308.1 K.
(a) What is Ecell (in V)? Report your answer to three decimal places in standard notation
(b) Which one of the following chemical reactions describes the process occurring in the
electrochemical cell?
412(s) + 5CIO4 (aq) + 4H20(1) → 8103 (ag) + 5CI (aq) + 8H* (ag)
24103 (aq) + 10CI (aq) + 24H*(aq) → 812(s) + 10CIO4 (aq)
8103 (aq) + 5CI (aq) + 8H*(aq) → 412(s) + 5CIO4 (aq) +
4H20(1)
812(s) + 10CIO4 (aq) → 24103 (aq) + 10CI (aq) + 24H*(aq)
(c) What is AG (in kJ/mol)? Report your answer to three significant figures in scientific notation
Transcribed Image Text:the E°cell is 0.194V, I could not get the rest of them right, plz show the full steps with calculations, thx a lot 2103 (aq) + 12H*(aq) + 10e¯ = 12(s) + 6H20(1) E° = 1.195 V clo4 (aq) + 8H*(aq) + 8e = CI (aq) + 4H2O(1) E° = 1.389 V Consider the electrochemical cell where one of the half cells is comprised of a Pt electrode in a solution containing 103 (aq) at a concentration of 2.27 M and I2(s) with a H* concentration of 3.02 M. The other half cell is comprised of a Pt electrode in a solution containing CIO4 (aq) at a concentration of 6.00 M and CI (aq) at a concentration of 5.87 x 10-4 M with a H* concentration of 3.30 x 10-5 M. The temperature of the cell is 308.1 K. (a) What is Ecell (in V)? Report your answer to three decimal places in standard notation (b) Which one of the following chemical reactions describes the process occurring in the electrochemical cell? 412(s) + 5CIO4 (aq) + 4H20(1) → 8103 (ag) + 5CI (aq) + 8H* (ag) 24103 (aq) + 10CI (aq) + 24H*(aq) → 812(s) + 10CIO4 (aq) 8103 (aq) + 5CI (aq) + 8H*(aq) → 412(s) + 5CIO4 (aq) + 4H20(1) 812(s) + 10CIO4 (aq) → 24103 (aq) + 10CI (aq) + 24H*(aq) (c) What is AG (in kJ/mol)? Report your answer to three significant figures in scientific notation
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