The earth's surface has a negative surface charge density of 10 Ci The potential difference of 400 kV between the top of the atmosphere and the surface results (due to the low conductivity of the lower atmosphere) in a current of only 1800 A over the entire globe. If there were no mechanism of sustaining atmospheric electric field, how much time (roughly) would be required to neutralise the earth's surface? (This never happens in practice because there is a mechanism to replenish electric charges, namely the continual thunderstorms and lightning in different parts of the globe). (Radius of earth = 6.37 x 106 m.)

icon
Related questions
Question
100%
The earth's surface has a negative surface charge density of 10-9 C m-2. The potential
difference of 400 kV between the top of the atmosphere and the surface results (due to
the low conductivity of the lower atmosphere) in a current of only 1800 A over the entire
globe. If there were no mechanism of sustaining atmospheric electric field, how much
time (roughly) would be required to neutralise the earth's surface? (This never happens
in practice because there is a mechanism to replenish electric charges, namely the
continual thunderstorms and lightning in different parts of the globe). (Radius of earth
%3D
6.37 x 10° m.)
Transcribed Image Text:The earth's surface has a negative surface charge density of 10-9 C m-2. The potential difference of 400 kV between the top of the atmosphere and the surface results (due to the low conductivity of the lower atmosphere) in a current of only 1800 A over the entire globe. If there were no mechanism of sustaining atmospheric electric field, how much time (roughly) would be required to neutralise the earth's surface? (This never happens in practice because there is a mechanism to replenish electric charges, namely the continual thunderstorms and lightning in different parts of the globe). (Radius of earth %3D 6.37 x 10° m.)
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer