The dynamic modulus of concrete is obtained for two different concrete mixes.For the first mix, n1 = 33, ī = 115.1 and s1 = 0.47 psi. For the second mix, n2 = 31,y = 114.6 and s2 = 0.38.(a) Test, with a = 0.05, the null hypothesis of equality of mean dynamicmodulus versus the two-sided alternative.(b)Obtain a 95% confidence interval for the difference in mean dynamicmodulus.

Name: The dynamic modulus of concrete is obtained for two different concret
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: The dynamic modulus of concrete is obtained for two different concrete mixes.For the first mix, n1 = 33, ī = 115.1 and s1 = 0.47 psi. For the second mix, n2 = 31,y = 114.6 and s2 = 0.38.(a) Test, with a = 0.05, the null hypothesis of equality of mea

a)From the given information,sp=n1-1s12+n2-1s22n1+n2-2=33-10.472+31-10.38233+31-2=11.400862=0.4288

Math

Statistics

The dynamic modulus of concrete is obtained for two different concrete mixes. For the first mix, n = 33, ī = 115.1 and s, = 0.47 psi. For the second mix, n2 = 31, j = 114.6 and s2 = 0.38. %3D (a) Test, with a = 0.05, the null hypothesis of equality of mean dynamic modulus versus the two-sided alternative. (b) Obtain a 95% confidence interval for the difference in mean dynamic modulus.

The dynamic modulus of concrete is obtained for two different concrete mixes. For the first mix, n = 33, ī = 115.1 and s, = 0.47 psi. For the second mix, n2 = 31, j = 114.6 and s2 = 0.38. %3D (a) Test, with a = 0.05, the null hypothesis of equality of mean dynamic modulus versus the two-sided alternative. (b) Obtain a 95% confidence interval for the difference in mean dynamic modulus.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 139 to 189 cm and weights of 39 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x=167.70 cm, y=81.43 kg, r=0.324, P-value=0.001, and y=−101+1.06x. Find the best predicted value of y (weight) given an adult male who is 151 cm tall. Use a 0.10 significance level. Question content area bottom Part 1 The best predicted value of y for an adult male who is 151 cm tall is enter your response here kg. (Round to two decimal places as needed.)
Match each Test Situation with the correct Critical Value. For a two-sided test, find only the positive value. Test Situation Two samples, 1 = 25.3, I2 H.: P1 - 2 po, and a 0.01 %3D Two samples, n = 28, Ha: µd > 0, and a 0.01 dv One sample, ni = - 35, п2 41, Ha: p1 – p2 0, and a = 0.01 %3D %3D One sample of x's and y's, n = 114, Ha: p < 0, and a = 0.001 One sample, o is known, n = 68, Ha:µ # Ho, and a = 0.05 One sample, o is unknown, n = 76, H. : µ < Ho, and a 0.05 Critical Value a. 1.960 b. -3.165 C. 2.473 d. 2.326 e. 2.576 f. -1.294 g. -1.665 h. 2.426
Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 139 to 188 cm and weights of 38 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 167.62 cm, y = 81.37 kg, r 0.113, P-value = 0.263, and y = - 105+1.01x. Find the best predicted value of y (weight) given an adult male who is 142 cm tall. Use a 0.05 significance level. %3D The best predicted value of y for an adult male who is 142 cm tall is kg. (Round to two decimal places as needed.)
NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6 Step 1 of 2 : Suppose a sample of 595 people is drawn. Of these people, 315 passed out at G forces greater than 6. Using the data, estimate the proportion of people who pass out at more than 6 Gs. Enter your answer as a fraction or a decimal number rounded to three decimal places.
Suppose μ₁ and ₂ are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 8, x = 115.6, $₁=5.09, n = 8, y = 129.5, and s₂ = 5.33. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) USE SALT Does the interval suggest that precise information about the value of this difference is available? O Because the interval is so narrow, it appears that precise information is available. O Because the interval is so wide, it appears that precise information is available. O Because the interval is so narrow, it appears that precise information is not available. O Because the interval is so wide, it appears that precise information is not available.
For 50 randomly selected speed dates, attractiveness ratings by males of their female date partners (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10. The 50 paired ratings yield x=6.3, y=6.0, r=−0.257, P-value=0.072, and y=7.92−0.300x. Find the best predicted value of y (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x=3. Use a 0.05 significance level. The best predicted value of y when x=3 is? (Round to one decimal place as needed.)
An experiment to compare the tension bond strength of polymer latex modified mortar (Portland cement mortar to which polymer latex emulsións have been added during mixing) to that of unmodified mortar resulted in x = 18.11 kgf/cm2 for the modified mortar (m = 42) and y = 16.88 kgf/cm2 for the unmodified mortar (n = 31). Let ₁ and ₂ be the true average tension bond strengths for the modified and unmodified mortars, respectively. Assume that the bond strength distributions are both normal. (a) Assuming that o₁ = 1.6 and ₂ = 1.3, test Ho: ₁ - ₂ = 0 versus H₂: H₁ - H₂> 0 at level 0.01. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) Z = P-value = State the conclusion in the problem context. O Fail to reject Ho. The data suggests that the difference in average tension bond strengths exceeds 0. Fail to reject Ho. The data does not suggest that the difference in average tension bond strengths…
what is the relative frequency of yields in sample A that were greater than 21.5 and less than or equal to 22.5 q/ha? i am getting the wrong one. its saying mine is incorrect.