The drying time of a type of paint under specified test conditions is known to be normally distributed with a mean value of 75 min and a stand ard deviation of 9 min. Chemists have proposed a new additive desinged to decrease average drying time. It is believed that drying times with this additive will remain normally distributed with o = 9. Because of the expense associated with the additive, evidence should strongly suggest an improvement in aver age dry- ing time before such a conclusion is adopted. Let u denote the true average drying time when the additive is used. The appropriate hypotheses are Ho :µ = 75 versus Ha : µ < 75.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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The drying time of a type of paint under specified test conditions is known to be normally
distributed with a mean value of 75 min and a stand ard deviation of 9 min. Chemists have
proposed a new additive desinged to decrease average drying time. It is believed that drying
times with this additive will remain normally distributed with o = 9. Because of the expense
associated with the additive, evidence should strongly suggest an improvement in aver age dry-
ing time before such a conclusion is adopted. Let u denote the true aver age drying time when
the additive is used. The appropriate hypotheses are Ho : u = 75 versus Ha : µ < 75.
Transcribed Image Text:The drying time of a type of paint under specified test conditions is known to be normally distributed with a mean value of 75 min and a stand ard deviation of 9 min. Chemists have proposed a new additive desinged to decrease average drying time. It is believed that drying times with this additive will remain normally distributed with o = 9. Because of the expense associated with the additive, evidence should strongly suggest an improvement in aver age dry- ing time before such a conclusion is adopted. Let u denote the true aver age drying time when the additive is used. The appropriate hypotheses are Ho : u = 75 versus Ha : µ < 75.
Suppose that in the problem noted in question 7 we have a type I error rate of 0.10. What
would be the type II error rate if the null hypothesis were false because u = 72? That is, what
is B(72)?
Transcribed Image Text:Suppose that in the problem noted in question 7 we have a type I error rate of 0.10. What would be the type II error rate if the null hypothesis were false because u = 72? That is, what is B(72)?
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