### Example Problem: Gravitational Forces in the Sun-Earth-Moon System#### Problem Description:The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force \(\vec{F}_{SM}\) that the sun exerts on the moon is perpendicular to the force \(\vec{F}_{EM}\) that the earth exerts on the moon. The masses are:- Mass of the sun (\(m_{S}\)) = \(1.99 \times 10^{30}\) kg- Mass of the earth (\(m_{E}\)) = \(5.98 \times 10^{24}\) kg- Mass of the moon (\(m_{M}\)) = \(7.35 \times 10^{22}\) kgThe distances shown in the drawing are:- Distance between the sun and the moon (\(r_{SM}\)) = \(1.50 \times 10^{11}\) m- Distance between the earth and the moon (\(r_{EM}\)) = \(3.85 \times 10^{8}\) mDetermine the magnitude of the net gravitational force on the moon.#### Diagram Explanation:The diagram illustrates the following key points:- The Sun is represented as a yellow star on the left side of the diagram.- The Earth is depicted as a blue sphere with green continents at a lower vertical position.- The Moon is shown as a smaller gray sphere in the upper region of the drawing, located such that it forms a right angle with lines extending from the Earth and the Sun.- Two forces are acting on the Moon: - \(\vec{F}_{SM}\) (blue arrow pointing from the Sun to the Moon) represents the gravitational force exerted by the Sun on the Moon. - \(\vec{F}_{EM}\) (blue arrow pointing from the Earth to the Moon) represents the gravitational force exerted by the Earth on the Moon. - The distance \(r_{SM}\) is the horizontal distance between the Sun and the Moon. - The distance \(r_{EM}\) is the vertical distance between the Earth and the Moon.### Calculation:Fill in the calculated values to determine the net gravitational force on the Moon:\[\text{Number: } \_\_\_\_\_\_\]\[\text{Units: } \_\_\_\_\

Answered: Image /qna-images/answer/b15aed62-59bb-4a4b-98ac-11187c06f2a9.jpg

The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force FSM that the sun exerts moon is perpendicular to the force FEM that the earth exerts on the moon. The masses are: mass of sun = 1.99 × 1030 kg, ma = 5.98 x 1024 kg, mass of moon = 7.35 x 1022 kg. The distances shown in the drawing are rsM = 1.50 × 1011 m and EM = 3.85 Determine the magnitude of the net gravitational force on the moon. Number : Sun Inits TSM FSM FEM Earth Moon TEM

The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force FSM that the sun exerts moon is perpendicular to the force FEM that the earth exerts on the moon. The masses are: mass of sun = 1.99 × 1030 kg, ma = 5.98 x 1024 kg, mass of moon = 7.35 x 1022 kg. The distances shown in the drawing are rsM = 1.50 × 1011 m and EM = 3.85 Determine the magnitude of the net gravitational force on the moon. Number : Sun Inits TSM FSM FEM Earth Moon TEM

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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