The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force FSM that the sun exerts on the moon is perpendicular to the force FEM that the earth exerts on the moon. The masses are: mass of sun = 1.99 x 1030 kg, mass of earth = 5.98 x 1024 kg, mass of moon = 7.35 x 1022 kg. The distances shown in the drawing are rsM = 1.50 x 1011 m and rEM = 3.85 x 108 m. Determine the magnitude of the net gravitational force on the moon. Sun TSM FSM TEM Earth Moon EM
Gravitational force
In nature, every object is attracted by every other object. This phenomenon is called gravity. The force associated with gravity is called gravitational force. The gravitational force is the weakest force that exists in nature. The gravitational force is always attractive.
Acceleration Due to Gravity
In fundamental physics, gravity or gravitational force is the universal attractive force acting between all the matters that exist or exhibit. It is the weakest known force. Therefore no internal changes in an object occurs due to this force. On the other hand, it has control over the trajectories of bodies in the solar system and in the universe due to its vast scope and universal action. The free fall of objects on Earth and the motions of celestial bodies, according to Newton, are both determined by the same force. It was Newton who put forward that the moon is held by a strong attractive force exerted by the Earth which makes it revolve in a straight line. He was sure that this force is similar to the downward force which Earth exerts on all the objects on it.
![**Current Attempt in Progress**
The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force \(\vec{F}_{SM}\) that the sun exerts on the moon is perpendicular to the force \(\vec{F}_{EM}\) that the earth exerts on the moon. The masses are: mass of sun = \(1.99 \times 10^{30}\) kg, mass of earth = \(5.98 \times 10^{24}\) kg, mass of moon = \(7.35 \times 10^{22}\) kg. The distances shown in the drawing are \(r_{SM} = 1.50 \times 10^{11}\) m and \(r_{EM} = 3.85 \times 10^{8}\) m. Determine the magnitude of the net gravitational force on the moon.
**Diagram Explanation**
- The diagram displays the sun, earth, and moon aligned linearly.
- The force \(\vec{F}_{SM}\) is a vector pointing from the sun to the moon.
- The force \(\vec{F}_{EM}\) is a vector pointing from the earth to the moon.
- The distances \(r_{SM}\) and \(r_{EM}\) represent the distances from the sun to the moon and from the earth to the moon, respectively.
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