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The downward forces represent the weights of machinery on the beam shown in (Figure 1). Assume the beam is uniform and has a mass of 280 kg .  Part A Calculate FA for the beam.   Part B Calculate FB for the beam.

The downward forces represent the weights of machinery on the beam shown in (Figure 1). Assume the beam is uniform and has a mass of 280 kg .  Part A Calculate FA for the beam.   Part B Calculate FB for the beam.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The downward forces represent the weights of machinery on the beam shown in (Figure 1). Assume the beam is uniform and has a mass of 280 kg . 

Part A

Calculate FA for the beam.
 

Part B

Calculate FB for the beam.
This image depicts a beam supported at two points with several forces acting on it. The beam is horizontal, and the forces are represented by vertical arrows indicating their direction and magnitude. 1. **Support Forces:** - \(\vec{F}_A\): Upward force at the left end of the beam. - \(\vec{F}_B\): Upward force at the right end of the beam. 2. **Applied Forces:** - 4300 N: Downward force located 2 meters from the left end. - 3100 N: Downward force located 6 meters from the left end (or 4 meters from the 4300 N force). - 2200 N: Downward force located 9 meters from the left end (or 3 meters from the 3100 N force). 3. **Distances:** - The total length of the beam is interpreted based on the sum of individual sections: 2 m + 4 m + 3 m + 1 m = 10 m. - Distance between forces and supports are clearly marked to depict precise force application points. The diagram provides a classic scenario for solving static equilibrium problems, where the sum of forces and moments about any point must be zero for the system to be in equilibrium.
Transcribed Image Text:This image depicts a beam supported at two points with several forces acting on it. The beam is horizontal, and the forces are represented by vertical arrows indicating their direction and magnitude. 1. **Support Forces:** - \(\vec{F}_A\): Upward force at the left end of the beam. - \(\vec{F}_B\): Upward force at the right end of the beam. 2. **Applied Forces:** - 4300 N: Downward force located 2 meters from the left end. - 3100 N: Downward force located 6 meters from the left end (or 4 meters from the 4300 N force). - 2200 N: Downward force located 9 meters from the left end (or 3 meters from the 3100 N force). 3. **Distances:** - The total length of the beam is interpreted based on the sum of individual sections: 2 m + 4 m + 3 m + 1 m = 10 m. - Distance between forces and supports are clearly marked to depict precise force application points. The diagram provides a classic scenario for solving static equilibrium problems, where the sum of forces and moments about any point must be zero for the system to be in equilibrium.
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